JavaScript 99Bottles - 无限循环

Question

（我已经知道这不是 99 瓶代码挑战的最优雅的解决方案，但我真的很想知道将来如何不重复这个错误。）

当它在控制台中运行时，它会重复

(count === 0)

条件，并且除了

"0 bottles of beer"

控制台日志之外不重复任何内容，直到崩溃。

我尝试在计数减至 0 后使用“break”语句，但没有取得任何成功。

let count = 99;

function bottlesOfBeer() {
    while (count >= 0) {
        if (count > 0) {
            console.log(count + " bottles of beer on the wall, " + count + " bottles of beer,");
            count--;
            console.log(" take one down, pass it around, " + count + " bottles of beer on the wall.");  
        };

        if (count === 0) {
            console.log(count + " bottles of beer on the wall, " + count + " bottles of beer. Go to the store, buy some more, 99 bottles of beer on the wall.");
        } //*this is where I tried the break statement*
    }
};

bottlesOfBeer();

Answer 1

仅当

count

大于 0 时才递减，因此它永远不会低于 0；但只要

count >= 0

，循环就会继续。

Answer 2

这是更正后的代码：

function bottlesOfBeer() {
  var count = 99;
  while (count > 0) {
    console.log(count + " bottles of beer on the wall, " + count + " bottles of beer,");
    count--;
    console.log(" take one down, pass it around, " + count + " bottles of beer on the wall.");  
  }
  console.log(count + " bottles of beer on the wall, " + count + " bottles of beer. Go to the store, buy some more, 99 bottles of beer on the wall.");
};

bottlesOfBeer();

请阅读并理解 - 如果您有疑问，请询问。
在代码中，

count

设置为99。
当

while

变为零时，

count

循环停止。
当循环存在时，

count

为零，并且记录歌曲的相应行。
我已经删除了空行...
除此之外 - 你的代码非常整洁：没有奇怪的缩进（你不会相信我所看到的 - 并不是它会影响执行，只是更容易阅读）。

Answer 3

将

while (count >= 0)

变成

while (count > 0)

就可以开始了！

问题是，当它达到零时，您只需记录消息而不再减少它，因此它保持为零并且

(count >= 0)

始终为真。

Answer 4

*let x = 99
let y = x - 1
function beer() {
    while (x > 1) {
        x--
        y--
        console.log(x + " bottles of bear on the wall, " + x + " bottles of bear. Take one down and pass it around, " + y + " bottles of bear on the wall.")
    }
}*