如何使用 python pandas 选择日期大于特定日期的文件？

Question

以下是以下文件夹中的文件：

C：emporary_location ile_name_20240901.csv C：emporary_location ile_name_20240902.csv C：emporary_location ile_name_20240903.csv C：emporary_location ile_name_20240904.csv C：emporary_location ile_name_20240905.csv C：emporary_location ile_name_20240906.csv C：emporary_location ile_name_20240907.csv C：emporary_location ile_name_20240908.csv C：emporary_location ile_name_20240909.csv C：emporary_location ile_name_20240910.csv C：emporary_location ile_name_20240911.csv C：emporary_location ile_name_20240912.csv C：emporary_location ile_name_20240913.csv

这是我用来仅选择一个文件的代码，它只会读取该文件，

import pandas as pd, numpy as np
from numpy import *
import glob
import os
import os.path
import duckdb

_path = r'C: emporary_location\'

_frame = []

for loc in glob.glob(_path + '*.csv'):
    if "20240905" in loc:
        print('Loading', loc)
        data = pd.read_csv(loc, low_memory=False)

如何使用上面相同的代码来选择日期大于特定日期的文件？ 例如：

for loc in glob.glob(_path + '*.csv'):
    if 20240905 > loc:
        print('Loading', loc)
        data = pd.read_csv(loc, low_memory=False)

代码应打印以下文件。

C：emporary_location ile_name_20240906.csv C：emporary_location ile_name_20240907.csv C：emporary_location ile_name_20240908.csv C：emporary_location ile_name_20240909.csv C：emporary_location ile_name_20240910.csv C： emporary_location ile_name_20240911.csv C：emporary_location ile_name_20240912.csv C：emporary_location ile_name_20240913.csv

Answer 1

尝试获取最后 8 位数字，不包括

.csv

if int(loc[-12:-4]) > 20240905: