有没有办法将“RPG”菜单与“clickMSG”功能连接起来？

Question

我想将“RPG”菜单与“clickMSG”功能连接起来。

运行代码时没有收到错误，但连接颜色为白色，因此未分配给任何内容。 这是代码：

class gui(QMainWindow): 
   def __init__(self, parent = None): 
      super(gui, self).__init__(parent)
      layout = QHBoxLayout()
      menu = self.menuBar()  
      file = menu.addMenu("New Account") 
      file.addAction("file") 

      file2 = menu.addMenu('RGP')   
      rpg = QAction("RGP") 
      file2.triggered[QAction].connect(self.clickMSG)
      
   def clickMSG(self): 
      msg = QMessageBox()  
      msg.setText("This is your RGP") 
      msg.setWindowTitle("This is an RGP") 
      msg.setIcon(QMessageBox.Information)
      pwo = PasswordGenerator()  
      passwrd = pwo.shuffle_password(string.ascii_letters, 10)   
        
def main(): 
   app = QApplication(sys.argv)  
   ex = gui()  
   ex.show()
   
   sys.exit(app.exec_())
if __name__ == '__main__':
   main()

Answer 1

您应该像制作第一个菜单栏按钮一样制作第二个菜单栏按钮。

对通过 addMenu() 方法提供的项目使用 addAction() 方法。

import sys
from PyQt5.QtWidgets import QMessageBox, QAction, QHBoxLayout, QApplication, QWidget, QPushButton, QVBoxLayout, QMainWindow
from PyQt5.QtCore import pyqtProperty

class gui(QMainWindow): 
    def __init__(self, parent = None): 
        super(gui, self).__init__(parent)
        layout = QHBoxLayout()
        menu = self.menuBar()  
        file = menu.addMenu("New Account") 
        file.addAction("file") 

        file2 = menu.addMenu('RGP-1')
        #rpg = QAction("RGP")
        file2.addAction("RGP-2") 
        file2.triggered[QAction].connect(self.clickMSG)

    def clickMSG(self):
        print('here !')
        msg = QMessageBox()  
        msg.setText("This is your RGP") 
        msg.setWindowTitle("This is an RGP") 
        msg.setIcon(QMessageBox.Information)
        #pwo = PasswordGenerator()  
        #passwrd = pwo.shuffle_password(string.ascii_letters, 10)   
    
def main(): 
    app = QApplication(sys.argv)  
    ex = gui()  
    ex.show()

    sys.exit(app.exec_())

if __name__ == '__main__':
   main()

希望这有帮助