[当我尝试通过API登录(电子邮件和密码参数)时,数据以行格式传递,但是我想以表单格式发布数据。由于这个问题,当我传递数据时,它不接受参数值,并显示null并给出错误。那么,我该如何解决这个问题呢?
只需添加带有json_data的标头。
Future<login> requestLogin(String username, String password , String device_id) async {
Map<String, String> headers = {"Content-type": "application/x-www-form-urlencoded"};
var json_body = { 'email' : username , 'password': password ,'device_id': device_id};
if(token != null){
headers.addAll({"Authorization" : "Bearer "+token});
}
// make POST request
final response = await http.post(baseUrl+ "/login", headers: headers, body: json_body);
print(response.body);
if (response.statusCode == 200) {
// If server returns an OK response, parse the JSON.
// return Post.fromJson(json.decode(response.body));
print(response.body);
return login.fromJson(json.decode(response.body));
} else {
// If that response was not OK, throw an error.
throw Exception(response.body);
}
}
对于您的发帖请求,只需像这样传递您的参数
您的发帖请求应如下所示。
response = await http.post("your_api_url",
body:{"email" : "value",
"password" : "value"});