PostgreSQL中动态区间的累积和

问题描述 投票:1回答:3

我有一张名为data_users的下表

 id   |     created_at
-------+---------------------
 20127 | 2015-01-31 04:23:46
 21468 | 2015-02-04 07:50:34
 21571 | 2015-02-04 08:23:50
 20730 | 2015-03-12 10:20:16
 19955 | 2015-03-30 07:44:35
 20148 | 2015-04-17 13:03:26
 21552 | 2015-05-07 19:00:00
 20145 | 2015-06-02 03:12:46
 21467 | 2015-06-03 13:21:51
 21074 | 2015-07-03 19:00:00

我正在尝试查找在Postgres中为动态间隔生成累积总和的查询。

SELECT DISTINCT DATE_TRUNC('DAY', GREATEST(d.date, from)) AS DATE,
           SUM(COALESCE(COUNT(u.id), 0)::INT) OVER (ORDER BY DATE)
FROM (SELECT GENERATE_SERIES(MIN(created_at)::DATE, to::DATE, '1 DAY'::INTERVAL) AS date
        FROM data_users) d
LEFT OUTER JOIN data_users u ON u.created_at::DATE = d.date::DATE
GROUP BY DATE ORDER BY DATE;

这将返回正确的天数累计总和,但我也想支持其他间隔。

我想支持像MONTHYEARWEEK这样的时间间隔。我需要在查询中更改哪些内容才能支持?

sql postgresql
3个回答
2
投票

使用案例表达式的想法:

SELECT x.date,
       count( case when u.created_at >= x.date and u.created_at < x.date + interval '1' day 
              then u.id end ) as int_1_day,
       count( case when u.created_at >= x.date and u.created_at < x.date + interval '7' day 
              then u.id end ) as int_1_week,
       count( case when u.created_at >= x.date and u.created_at < x.date + interval '1' month 
              then u.id end ) as int_1_month,
       count( case when u.created_at >= x.date and u.created_at < x.date + interval '1' year 
              then u.id end ) as int_1_year
FROM (
  SELECT GENERATE_SERIES(MIN(created_at)::DATE, date '2015-07-31', '1 DAY'::INTERVAL) AS date
  FROM data_users
) x
LEFT JOIN data_users u
ON u.created_at BETWEEN x.date and x.date + interval '1' year
GROUP BY x.date
ORDER BY x.date

现场演示:http://sqlfiddle.com/#!17/05e1a/10


注意:连接条件ON u.created_at BETWEEN x.date and x.date + interval '1' year必须使用您需要计算计数的最长间隔,在上面的示例中:+ interval '1' year


0
投票

让我们看看这次我是否理解。我假设您希望每个间隔都有单独的查询。 (他们可以连在一起。)另外我假设你想要累积整个系列。 (每组可以重新开始积累。)

每日积累可以更简单,仍然给出相同的结果:

\set from_date '''2015-01-01'''
\set to_date '''2015-12-31'''

select distinct 
    to_char(a.series_date, 'YYYY-MM-DD') as series_date,
    count(b.id)
from
    (
        select 
            generate_series(:from_date::date, :to_date::date, '1 day'::interval) as series_date
    ) a
    left outer join 
    data_users b 
    on date_trunc('day', b.created_at) <= a.series_date
group by
    series_date 
order by
    series_date;

数周:

select distinct 
    to_char(b.last_day_of_week, 'Day YYYY-MM-DD') as week_ending,
    count(c.id)
from
    (
        select
            series_date as last_day_of_week
        from
            (
                select 
                    generate_series(:from_date::date, :to_date::date, '1 day'::interval) as series_date
            ) a
        where
            extract('dow' from series_date) = 6
    ) b
    left outer join 
    data_users c 
    on date_trunc('day', c.created_at) <= b.last_day_of_week
group by
    week_ending 
order by
    week_ending;

结果:

     week_ending      | count 
----------------------+-------
 Saturday  2015-01-03 |     0
 Saturday  2015-01-10 |     0
 Saturday  2015-01-17 |     0
 Saturday  2015-01-24 |     0
 Saturday  2015-01-31 |     1
 Saturday  2015-02-07 |     3
 Saturday  2015-02-14 |     3
 Saturday  2015-02-21 |     3
 Saturday  2015-02-28 |     3
 Saturday  2015-03-07 |     3
 Saturday  2015-03-14 |     4
 Saturday  2015-03-21 |     4
 Saturday  2015-03-28 |     4
 Saturday  2015-04-04 |     5
 Saturday  2015-04-11 |     5
 Saturday  2015-04-18 |     6
 Saturday  2015-04-25 |     6
 Saturday  2015-05-02 |     6
 Saturday  2015-05-09 |     7
 Saturday  2015-05-16 |     7
 Saturday  2015-05-23 |     7
 Saturday  2015-05-30 |     7
 Saturday  2015-06-06 |     9
 Saturday  2015-06-13 |     9
 Saturday  2015-06-20 |     9
 Saturday  2015-06-27 |     9
 Saturday  2015-07-04 |    10
 Saturday  2015-07-11 |    10
 Saturday  2015-07-18 |    10
 Saturday  2015-07-25 |    10
 Saturday  2015-08-01 |    10
 Saturday  2015-08-08 |    10
 Saturday  2015-08-15 |    10
 Saturday  2015-08-22 |    10
 Saturday  2015-08-29 |    10
 Saturday  2015-09-05 |    10
 Saturday  2015-09-12 |    10
 Saturday  2015-09-19 |    10
 Saturday  2015-09-26 |    10
 Saturday  2015-10-03 |    10
 Saturday  2015-10-10 |    10
 Saturday  2015-10-17 |    10
 Saturday  2015-10-24 |    10
 Saturday  2015-10-31 |    10
 Saturday  2015-11-07 |    10
 Saturday  2015-11-14 |    10
 Saturday  2015-11-21 |    10
 Saturday  2015-11-28 |    10
 Saturday  2015-12-05 |    10
 Saturday  2015-12-12 |    10
 Saturday  2015-12-19 |    10
 Saturday  2015-12-26 |    10
(52 rows)

几个月,显示每月最后一天的总数:

select distinct 
    b.last_day_of_month,
    count(c.id)
from
    (
        select
            (extract(year from series_date) || '-' || extract(month from series_date) || '-' || '01')::date + 
            '1 month'::interval - 
            '1 day'::interval as last_day_of_month
        from
            (
                select 
                    generate_series(:from_date::date, :to_date::date, '1 month'::interval) as series_date
            ) a
    ) b
    left outer join 
    data_users c 
    on date_trunc('day', c.created_at) <= b.last_day_of_month
group by
    last_day_of_month 
order by
    last_day_of_month;

结果:

  last_day_of_month  | count 
---------------------+-------
 2015-01-31 00:00:00 |     1
 2015-02-28 00:00:00 |     3
 2015-03-31 00:00:00 |     5
 2015-04-30 00:00:00 |     6
 2015-05-31 00:00:00 |     7
 2015-06-30 00:00:00 |     9
 2015-07-31 00:00:00 |    10
 2015-08-31 00:00:00 |    10
 2015-09-30 00:00:00 |    10
 2015-10-31 00:00:00 |    10
 2015-11-30 00:00:00 |    10
 2015-12-31 00:00:00 |    10
(12 rows)

多年来我又增加了3行:

insert into data_users (id, created_at) values (30123, '2016-01-02 03:12:46');
insert into data_users (id, created_at) values (30234, '2016-03-03 13:21:51');
insert into data_users (id, created_at) values (30345, '2016-07-03 19:00:00');

并更改了to_date:

\set to_date '''2017-12-31'''

select distinct 
    extract('year' from b.last_day_of_year) as year,
    count(c.id)
from
    (
        select
            series_date + '1 year'::interval - '1 day'::interval as last_day_of_year
        from
            (
                select 
                    generate_series(:from_date::date, :to_date::date, '1 year'::interval) as series_date
            ) a
    ) b
    left outer join 
    data_users c 
    on date_trunc('day', c.created_at) <= b.last_day_of_year
group by
    year
order by
    year;

结果:

 year | count 
------+-------
 2015 |    10
 2016 |    13
 2017 |    13
(3 rows)

我们怎么样?


-1
投票

这听起来太容易了;我错过了什么吗?您可以在PostgreSQL中指定所需的所有间隔,如下所示:

select
     '1 day'::interval,
     '1 week'::interval,
     '1 month'::interval,
     '1 year'::interval;
 interval | interval | interval | interval 
----------+----------+----------+----------
 1 day    | 7 days   | 1 mon    | 1 year
(1 row)
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