如何减慢pygame中的刷新率？ [重复]

Question

我是 python 新手，我正在尝试使用 pygame 制作一个简单的平台游戏。我的问题是，当我使用

while

循环使方块下落直到它到达屏幕底部时，它会立即移动到那里，而我看不到它发生。然而，当我使用

if

语句将块从一侧移动到另一侧时，我可以看到这种情况发生。如何才能减慢下落的方块的速度，使其可见？

我大部分时间都在关注教程，但想添加我自己的东西。

clock = pygame.time.Clock()
fps = 60
run = True
while run:
    clock.tick(fps)
    keys = pygame.key.get_pressed()
    if keys[pygame.K_a] and x > 0:
        x = x - 5
    if keys[pygame.K_d] and x < (500 - width):
        x = x + 5
    if keys[pygame.K_s]: #this is the portion that is too fast. 
        while y < (500 - height):
            y = y + 5    
    player = pygame.draw.rect(screen, (player_color), (x,y,width,height))
    pygame.display.update()

我也尝试将整个

while ... y = y + 5

代码放入

if

中；这减慢了它的速度，但只有当我按住

s

键时它才会移动。

Answer 1

如果你希望它完全“动画”下来，你应该添加在 while 循环中保持 pygame 屏幕/播放器更新的代码，否则你只是更改

y

而不更改屏幕。所以你的代码看起来有点像这样：

clock = pygame.time.Clock()
fps = 60
run = True
while run:
    clock.tick(fps)
    keys = pygame.key.get_pressed()
    if keys[pygame.K_a] and x > 0:
        x = x - 5
    if keys[pygame.K_d] and x < (500 - width):
        x = x + 5
    if keys[pygame.K_s]: #this is the portion that is too fast. 
        while y < (500 - height):
            y = y + 5 
            player = pygame.draw.rect(screen, (player_color), (x,y,width,height)) # Make sure to update the player
            pygame.display.update() # Make sure to update the display
    player = pygame.draw.rect(screen, (player_color), (x,y,width,height))
    pygame.display.update()

更改 FPS：
但是，如果您确实想更改游戏循环的速度/本质上是每秒帧数，您可以简单地更改

fps

变量/

clock.tick()

参数。例如：

clock = pygame.time.Clock()
fps = 30 # This value is the amount of frames per second
run = True
while run:
    clock.tick(fps) # The argument (currently fps) passed into this method will change the frames per second
    keys = pygame.key.get_pressed()
    if keys[pygame.K_a] and x > 0:
        x = x - 5
    if keys[pygame.K_d] and x < (500 - width):
        x = x + 5
    if keys[pygame.K_s]: #this is the portion that is too fast. 
        while y < (500 - height):
            y = y + 5    
    player = pygame.draw.rect(screen, (player_color), (x,y,width,height))
    pygame.display.update()

您可以在

此处

阅读有关clock.tick()

方法的更多信息