我正在尝试将 Angular 4 动画应用于 html 元素列表,例如
facilities = ['<p> <span class="glyphicon glyphicon-hand-right"> </span> Text 1</p>',
'<p> <span class="glyphicon glyphicon-hand-right"></span>Text 2</p>',
'<p> <span class="glyphicon glyphicon-hand-right"></span> Text 3</p>',
'<p> <span class="glyphicon glyphicon-hand-right"></span> Text 4</p>',
];
一一使用以下代码:
animations: [
trigger('flyInOut', [
state('in', style({transform: 'translateX(0)'})),
transition('void => *', [
style({transform: 'translateX(-100%)'}),
animate(100)
]),
transition('* => void', [
animate(100, style({transform: 'translateX(100%)'}))
])
])
]
当我将此触发器放在列表元素上时,所有元素都会一次性出现在屏幕上。我想让它们一一出现。就像在 html 上获取文本 1,然后获取文本 2 一样。我怎样才能做到这一点?
更新: 使用交错:
HTML:
<ul [@listAnimation]="items.length">
<li *ngFor="let item of items" >
<div [innerHTML]="item"></div>
</li>
</ul>
打字稿:
....
animations: [
trigger('listAnimation', [
transition('* => *', [
query(':leave', [
stagger(500, [
animate(1000, style({ opacity: 0 }))
])
], { optional: true }),
query(':enter', [
style({ opacity: 0 }),
stagger(500, [
animate(1000, style({ opacity: 1 }))
])
], { optional: true })
])
...
可以通过角度动画回调以及用打字稿编写的一些帮助来完成
HTML:
<ul>
<li *ngFor="let item of listCopy;" (@flyInOut.done)="getNextItem()" [@flyInOut]="'in'" >
<ul>
<li *ngFor="let item of list" (@flyInOut.done)="getNextItem()" [@flyInOut]="'in'" >
<div [innerHTML]="item"></div>
</li>
</ul>
</li>
</ul>
打字稿:
.....
@Component({
....
animations: [
trigger('flyInOut', [
state('in', style({transform: 'translateX(0)'})),
transition('void => *', [
style({transform: 'translateX(-100%)'}),
animate(100)
]),
transition('* => void', [
animate(100, style({transform: 'translateX(100%)'}))
])
])
]
....
list = ['Item1', 'Item2', 'Item3', 'Item4'];
listCopy = [];
next: number = 0;
constructor(){
this.getNextItem();
}
getNextItem() {
if(this.next < this.list.length) {
this.listCopy.push(this.list[this.next++]);
}
}
Plunker(我放了1000ms来强调动画)