我有一个像这样的对象:
public class Marketplace {
private String name;
private int id;
private List<String> supportedLanguages;
}
我有一个输入Json格式的字符串,如下所示:
{
"name":"US",
"id":1,
"supportedLanguages":{"en_US", "es_US"}
}
我先尝试过类似的东西但失败了:
objectMapper.readValue(marketplaceInJsonString, Marketplace.class);
然后我尝试了类似的东西,但仍然失败了:
JsonNode jsonNode = objectMapper.readValue(marketplaceInJsonString, JsonNode.class);
Marketplace marketplace = new Marketplace(jsonNode.get("name").asText()), jsonNode.get("id").asInt(), jsonNode.findValuesAsText("supportedLanguages"));
我认为这里的关键问题是我没有找到将supportedLanguages映射为String列表的正确方法。
是否存在Json String输入的任何格式问题?
请帮忙,真的很感激。
你的json字符串无效json 改为
{
"name": "US",
"id": 1,
"supportedLanguages": [
"en_US",
"es_US"
]
}
测试代码:
String marketplaceInJsonString = "{\"name\":\"US\",\"id\":1,\"supportedLanguages\":[\"en_US\",\"es_US\"]}";
ObjectMapper objectMapper = new ObjectMapper();
Marketplace marketplace = objectMapper.readValue(marketplaceInJsonString, Marketplace.class);
System.out.println(marketplace);
//输出
Marketplace(name=US, id=1, supportedLanguages=[en_US, es_US])