仅从 URL 获取域名?

问题描述 投票:0回答:13

我正在尝试从 URL 字符串中提取域名。我快有了...我正在使用 URI

我有一个字符串..我的第一个想法是使用 Regex 但后来我决定使用 URI 类

http://www.google.com/url?sa=t&source=web&ct=res&cd=1&ved=0CAgQFjAA&url=http://www.test.com/&rct=j&q=test&ei=G2phS-HdJJWTjAfckvHJDA&usg=AFQjCNFSEAztaqtkaIvEzxmRm2uOARn1kQ

我需要将上面的内容转换为 google.com 和没有 www 的 google

我做了以下事情

Uri test = new Uri(referrer);
log.Info("Domain part : " + test.Host);

基本上这会返回 www.google.com ....如果可能的话,我想尝试返回 2 个表单...如上所述...

google.com 和谷歌

这可以通过 URI 实现吗?

c# uri
13个回答
29
投票

是的,可以使用:

Uri.GetLeftPart( UriPartial.Authority )

9
投票

使用 Nager.PublicSuffix

安装包 Nager.PublicSuffix

var domainParser = new DomainParser(new WebTldRuleProvider());

var domainName = domainParser.Get("sub.test.co.uk");
//domainName.Domain = "test";
//domainName.Hostname = "sub.test.co.uk";
//domainName.RegistrableDomain = "test.co.uk";
//domainName.SubDomain = "sub";
//domainName.TLD = "co.uk";

7
投票

我几乎尝试了所有方法,但都没有达到预期的结果。 所以这是我从 servermanfail 调整而来的方法。

tld 文件可在 https://publicsuffix.org/list/ 获取 我从 https://publicsuffix.org/list/ effective_tld_names.dat 获取该文件,解析它并搜索 tld。如果发布新顶级域名,只需下载最新文件。

玩得开心。

using System;
using System.Collections.Generic;
using System.IO;

namespace SearchWebsite
{
internal class NetDomain
{
    static public string GetDomainFromUrl(string Url)
    {
        return GetDomainFromUrl(new Uri(Url));
    }

    static public string GetDomainFromUrl(string Url, bool Strict)
    {
        return GetDomainFromUrl(new Uri(Url), Strict);
    }

    static public string GetDomainFromUrl(Uri Url)
    {
        return GetDomainFromUrl(Url, false);
    }

    static public string GetDomainFromUrl(Uri Url, bool Strict)
    {
        initializeTLD();
        if (Url == null) return null;
        var dotBits = Url.Host.Split('.');
        if (dotBits.Length == 1) return Url.Host; //eg http://localhost/blah.php = "localhost"
        if (dotBits.Length == 2) return Url.Host; //eg http://blah.co/blah.php = "localhost"
        string bestMatch = "";
        foreach (var tld in DOMAINS)
        {
            if (Url.Host.EndsWith(tld, StringComparison.InvariantCultureIgnoreCase))
            {
                if (tld.Length > bestMatch.Length) bestMatch = tld;
            }
        }
        if (string.IsNullOrEmpty(bestMatch))
            return Url.Host; //eg http://domain.com/blah = "domain.com"

        //add the domain name onto tld
        string[] bestBits = bestMatch.Split('.');
        string[] inputBits = Url.Host.Split('.');
        int getLastBits = bestBits.Length + 1;
        bestMatch = "";
        for (int c = inputBits.Length - getLastBits; c < inputBits.Length; c++)
        {
            if (bestMatch.Length > 0) bestMatch += ".";
            bestMatch += inputBits[c];
        }
        return bestMatch;
    }


    static private void initializeTLD()
    {
        if (DOMAINS.Count > 0) return;

        string line;
        StreamReader reader = File.OpenText("effective_tld_names.dat");
        while ((line = reader.ReadLine()) != null)
        {
            if (!string.IsNullOrEmpty(line) && !line.StartsWith("//"))
            {
                DOMAINS.Add(line);
            }
        }
        reader.Close();
    }


    // This file was taken from https://publicsuffix.org/list/effective_tld_names.dat

    static public List<String> DOMAINS = new List<String>();
}

}


6
投票

google.com 不保证与 www.google.com 相同(嗯,对于本示例来说,技术上是相同,但也可能不同)。

也许您实际上需要的是删除“顶级”域名和“www”子域名?然后就

split('.')
并获取最后一部分之前的部分!


5
投票

下面是一些代码,仅提供 SLD 加上 gTLD 或 ccTLD 扩展名(请注意下面的例外情况)。我不关心 DNS。

理论如下:

  • 任何低于 3 个令牌的内容都保持原样,例如“localhost”、“domain.com”,否则:最后一个令牌必须是 gTLD 或 ccTLD 扩展名。
  • 倒数第二个标记如果长度足够,则被视为扩展的一部分 < 3 OR if included in a list of exceptions.
  • 最后,之前的代币被视为 SLD。在此之前的任何内容都被视为子域或主机限定符,例如WWW.

至于代码,简短而甜蜜:

private static string GetDomainName(string url)
{
    string domain = new Uri(url).DnsSafeHost.ToLower();
    var tokens = domain.Split('.');
    if (tokens.Length > 2)
    {
        //Add only second level exceptions to the < 3 rule here
        string[] exceptions = { "info", "firm", "name", "com", "biz", "gen", "ltd", "web", "net", "pro", "org" }; 
        var validTokens = 2 + ((tokens[tokens.Length - 2].Length < 3 || exceptions.Contains(tokens[tokens.Length - 2])) ? 1 : 0);
        domain = string.Join(".", tokens, tokens.Length - validTokens, validTokens);
    }
    return domain;
}

明显的例外是,这不会处理 2 个字母的域名。因此,如果您足够幸运拥有 ab.com,则需要稍微调整代码。对于我们这些凡人来说,此代码将涵盖几乎所有 gTLD 和 ccTLD,除了一些非常奇特的。


3
投票

我认为您对“域名”的构成存在误解 - 不存在常见的“纯域名” - 如果您想要一致的结果,您需要定义这一点。
您只想去掉“www”部分吗? 然后有另一个版本,它剥离顶级域名(例如,剥离“.com”或“.co.uk”等部分?) 另一个答案提到 split(".") - 如果您想手动排除主机名的特定部分,则需要使用类似的东西,.NET 框架中没有任何东西可以完全满足您的要求 - 您需要实现这些事情自己做。


3
投票

我想出了以下解决方案(使用 Linq):

    public string MainDomainFromHost(string host)
    {
        string[] parts = host.Split('.');
        if (parts.Length <= 2)
            return host; // host is probably already a main domain
        if (parts[parts.Length - 1].All(char.IsNumber))
            return host; // host is probably an IPV4 address
        if (parts[parts.Length - 1].Length == 2 && parts[parts.Length - 2].Length == 2)
            return string.Join(".", parts.TakeLast(3)); // this is the case for co.uk, co.in, etc...
        return string.Join(".", parts.TakeLast(2)); // all others, take only the last 2
    }

1
投票

是的,我在这里发布了解决方案:http://pastebin.com/raw.php?i=raxNQkCF

如果您想删除扩展程序,只需添加

if (url.indexof(".")>-1) {url = url.substring(0, url.indexof("."))}


1
投票

Uri 的主机始终返回域名 (www.google.com),包括标签 (www) 和顶级域名 (com)。但通常您会想要提取中间部分。我就是这么做的

Uri uri;
bool result = Uri.TryCreate(returnUri, UriKind.Absolute, out uri);
if (result == false)
    return false;

//if you are sure it's not "localhost"
string domainParts = uri.Host.Split('.');
string topLevel = domainParts[domainParts.Length - 1]
string hostBody = domainParts[domainParts.Length - 2]
string label = domainParts[domainParts.Length - 3]

但是您确实需要检查domainParts.length,因为给定的uri通常类似于“google.com”。


0
投票

我为自己找到了一个解决方案,并且没有使用任何 TLD 或其他东西。

它利用了这样一个事实:所谓的主机名位于 Uri 的主机部分中,始终位于倒数第二个位置。子域名始终位于名称前面,TLD 始终位于名称后面。

看这里:

private static string GetNameFromHost(string host)
{
    if (host.Count(f => f == '.') == 1)
    {
        return host.Split('.')[0];
    }
    else
    {
        var _list = host.Split('.').ToList();
        return _list.ElementAt(_list.Count - 2);
    }
}

0
投票

看到这个

UriHostWithoutSubdomain
要点

请参阅一些测试的要点,但用法如下:

string subdomain = UriHostWithoutSubdomain.GetHostWithoutSubdomain("foo.example.com");
// subdomain == "example.com"

// this depends on the following more lower level:

bool hasSub = UriHostWithoutSubdomain.HasSubdomain("foo.example.com", out int index);
// hasSub == true, and index == 4. The latter can be used to get both the subdomain and the domain without subdomain

/// <summary>
/// `Uri` class does not allow getting a subdomain from the `uri.Host`.
/// This class provides a highly efficient method of getting a subdomain
/// if it exists on an input host / domain string (ideally sent in via
/// <see cref="Uri.Host"/>).
/// </summary>
public class UriHostWithoutSubdomain
{
    /// <summary>
    /// If subdomain detected returns the subdomain, else returns input value.
    /// If null returns null.
    /// </summary>
    /// <param name="host">Send in `Uri.Host`</param>
    public static string GetHostWithoutSubdomain(string host)
    {
        if(host == null)
            return null;

        if(!HasSubdomain(host, out int registrableDomainIndex))
            return host;

        string regDomain = host.Substring(registrableDomainIndex);
        return regDomain;
    }

    /// <summary>
    /// Detects if an input host string contains a subdomain. Is a highly efficient
    /// implementation: with NO allocations, and with two for loops sharing a single `int i`:
    /// one up to the first period, and one that continues from that point 
    ///
    /// and is NOT a validator of a domain string. For efficiency purposes
    /// that is not desirable, as the intended use-case as well as separation of concerns
    /// is that a `Uri.Host` value was input, or something like that.
    /// Relying on this allows us to provide this highly efficient algorithm, which essentially
    /// only needs to walk once through the string chars looking first for the first period,
    /// and then, if a second period is detected, it is established that a subdomain exists.
    /// If so, the out arg allows one to know where to take a substring to get the subdomain,
    /// or the second-level domain without it, etc.
    /// <para />
    /// </summary>
    /// <param name="host">Uri host / domain string</param>
    /// <param name="postSubdomainIndex">If subdomain exists, this will be set to the
    /// index at which the 'second-level domain' begins (after the subdomain and 1 AFTER the period,
    /// so in foo.example.com, index will be at 'e' in 'example.com').
    /// But if no subdomain (if FALSE), then this will be the position of the 'top-level' domain,
    /// e.g. at the 'c' in "com" in "example.com". If one wants they could use this to
    /// efficiently get the top-level domain and etc.</param>
    public static bool HasSubdomain(string host, out int postSubdomainIndex)
    {
        ArgumentNullException.ThrowIfNull(host);

        int i = 0;
        int len = host.Length;

        for(; i < len; i++)
            if(host[i] == '.')
                break;

        if(i >= len) {
            // no period at all
            postSubdomainIndex = 0;
            return false;
        }

        postSubdomainIndex = ++i;

        for(; i < len; i++)
            if(host[i] == '.')
                break;

        if(i >= len) {
            // no second period was found, so period was for TLD (top-level domain)
            return false;
        }

        // second period WAS found, and we are NOT at the end yet,
        // but we do NOT need to go further now, subdomain ends before first period,
        // we're now already at second

        return true;
    }
}

-1
投票

由于域名存在多种变体,并且不存在任何真正的权威列表来构成您所描述的“纯域名”,我过去只是求助于使用 Uri.Host。为了避免 www.google.com 和 google.com 显示为两个不同的域,我经常采取剥离 www 的方式。来自包含它的所有域,因为它几乎保证(几乎)指向同一个站点。这确实是唯一简单的方法,而且不会冒丢失某些数据的风险。


-2
投票
string domain = new Uri(HttpContext.Current.Request.Url.AbsoluteUri).GetLeftPart(UriPartial.Authority);
© www.soinside.com 2019 - 2024. All rights reserved.