我正在使用Cloud9 IDE,当我打开在SQLite中存储和检索的图像时,得到的是"Invalid or Unsupported Image Format"
。当我将convertToBinaryData
文件输入到writeTofile
函数中时,便会检索照片,因此这绝对与SQL有关。
有人可以协助您正确格式化吗?
def convertToBinaryData(filename):
#Convert digital data to binary format
with open(path, 'rb') as file:
blobData = file.read()
return blobData
def writeTofile(data, filename):
# Convert binary data to proper format and write it on Hard Disk
with open(filename, 'wb') as file:
advert = file.write(data)
@app.route("/place", methods=["GET", "POST"])
@login_required
def place():
if request.method == "GET":
return render_template("place.html")
if request.method == "POST":
我已经尝试了以下四个选项,但它们都不起作用。
'''Version 1'''
placing = "INSERT INTO food (category, title, description, shipping, photo, county, area, post_time, UID) VALUES (?,?,?,?,?,?,?,CURRENT_TIMESTAMP,?)"
ad_photo = convertToBinaryData(request.form.get("photo"))
db.execute(placing, (session["user_id"], request.form.get("category"), request.form.get("title"), request.form.get("description"), request.form.getlist("option[]"), ad_photo, request.form.get("county"), request.form.get("area")))
row = db.execute('SELECT photo FROM food')
print (str(row[0]))
writeTofile(row[0], "dan.jpg")
错误:file.write(数据)TypeError:需要一个类似字节的对象,而不是'dict'
'''Version 2'''
placing = "INSERT INTO food (category, title, description, shipping, photo, county, area, post_time, UID) VALUES (?,?,?,?,?,?,?,CURRENT_TIMESTAMP,?)"
ad_photo = convertToBinaryData(request.form.get("photo"))
db.execute(placing, (session["user_id"], request.form.get("category"), request.form.get("title"), request.form.get("description"), request.form.getlist("option[]"), ad_photo, request.form.get("county"), request.form.get("area")))
row = db.execute('SELECT photo FROM food')
print (row[0])
writeTofile(row[0], "dan.jpg")
错误:file.write(数据)TypeError:需要一个类似字节的对象,而不是'dict'
'''Version 3'''
placing = "INSERT INTO food (UID, category, title, description, shipping, photo, county, area, post_time) VALUES (?,?,?,?,?,?,?,?,CURRENT_TIMESTAMP)"
ad_photo = convertToBinaryData(request.form.get("photo"))
db.execute(placing, (session["user_id"], request.form.get("category"), request.form.get("title"), request.form.get("description"), request.form.getlist("option[]"), ad_photo, request.form.get("county"), request.form.get("area")))
row = db.execute('SELECT photo FROM food')
print (str(row[0]))
mystring = str(row[0])
b = mystring.encode('utf-8')
writeTofile(b, "dan.jpg")
错误:没有错误,但是创建的JPEG是“无效或不受支持的图像格式”
'''Version 4'''
sqliteConnection = sqlite3.connect('finance.db')
cursor = sqliteConnection.cursor()
placing = "INSERT INTO food (category, title, description, shipping, photo, county, area, post_time, UID) VALUES (?,?,?,?,?,?,?,CURRENT_TIMESTAMP,?)"
ad_photo = convertToBinaryData(request.form.get("photo"))
# Convert data into tuple format
data_tuple = (request.form.get("category"), request.form.get("title"), request.form.get("description"), request.form.get("option[]"), ad_photo, request.form.get("county"), request.form.get("area"), session["user_id"])
cursor.execute(placing, data_tuple)
sqliteConnection.commit()
print("Image and file inserted successfully as a BLOB into a table")
cursor.execute("SELECT photo from food")
record = cursor.fetchone()
writeTofile(record, "dan.jpg")
cursor.close()
错误:TypeError:需要一个类似字节的对象,而不是“元组”
好吧,我在写完所有错误然后尝试完全不同的方法后终于弄清楚了。感谢您的共鸣。
def place():
"""place an ad"""
if request.method == "GET":
return render_template("place.html")
if request.method == "POST":
sqliteConnection = sqlite3.connect('finance.db')
cursor = sqliteConnection.cursor()
placing = "INSERT INTO food (category, title, description, shipping, photo, county, area, post_time, uid) VALUES (?,?,?,?,?,?,?,CURRENT_TIMESTAMP,?)"
ad_photo = convertToBinaryData(request.form.get("photo"))
# Convert data into tuple format
data_tuple = ((request.form.get("category"), request.form.get("title"), request.form.get("description"), request.form.get("option[]"), ad_photo, request.form.get("county"), request.form.get("area"), session["user_id"]))
cursor.execute(placing, data_tuple)
sqliteConnection.commit()
print("Image and file inserted successfully as a BLOB into a table")
sqliteConnection = sqlite3.connect('finance.db')
cursor = sqliteConnection.cursor()
query = cursor.execute("SELECT * FROM food ORDER BY post_time DESC LIMIT 1")
for row in query:
pic = row[4]
writeTofile(pic, "dan.jpg")
sqliteConnection.commit()
cursor.close()
return render_template("placed.html")