我为Joomla编了一个表格。它工作得非常好，但现在突然间PHP处理无法正常工作。我试了十几件事让它发挥作用，但它不听我的意思。为什么？
这是代码：
<?php
echo '<html>
<table>
<form method="post" action="post">
<tr>
<td>Uporabniško ime</td>
<td><input type="text" name="up_ime" id="up_ime" size="20">
</td>
</tr>
<tr>
<td>Origin ID</td>
<td><input type="text" name="origin" id="origin" size="40">
</td>
</tr>
<tr>
<td></td>
<td align="right"><input type="submit" name="submit" value="Prijava"></td>
</tr>
</form>
</table>
</html>';
mysql_connect("localhost","username","password");
mysql_select_db("fifaslov_fut");
$up_ime = $_POST['up_ime'];
$origin = $_POST['origin'];
if(empty($up_ime) || empty($origin)){
echo("");
} else{
$order = "INSERT INTO futliga_pc_prijava (up_ime, origin) VALUES ('$up_ime','$origin')";
$result = mysql_query($order);
echo("<br>Uspešno ste se prijavili!");
}
mysql_close;
?>
你没有存储connection Variable
$con = mysql_connect("localhost","fifaslov_fut","bovo2978", "fifaslov_fut");
$up_ime = $_POST['up_ime'];
$origin = $_POST['origin'];
if(empty($up_ime) || empty($origin)){
echo("");
} else{
$order = "INSERT INTO futliga_pc_prijava (up_ime, origin) VALUES ('$up_ime','$origin')";
$result = mysql_query($con, $order);
echo("<br>Uspešno ste se prijavili!");
}
mysql_close($con);
只是一个建议使用mysqli