试图计算字符串中的单词

Question

我正在尝试分析字符串的内容。如果它在单词中混合了标点符号，我想用空格替换它们。

例如，如果Johnny.Appleseed！是：输入a * good＆farmer作为输入，则应该说有6个单词，但我的代码只将其视为0个单词。我不知道如何删除不正确的字符。

仅供参考：我正在使用python 3，我也无法导入任何库

string = input("type something")
stringss = string.split()

    for c in range(len(stringss)):
        for d in stringss[c]:
            if(stringss[c][d].isalnum != True):
                #something that removes stringss[c][d]
                total+=1
print("words: "+ str(total))

Answer 1

Simple loop based solution:

strs = "Johnny.Appleseed!is:a*good&farmer"
lis = []
for c in strs:
    if c.isalnum() or c.isspace():
        lis.append(c)
    else:
        lis.append(' ')

new_strs = "".join(lis)
print new_strs           #print 'Johnny Appleseed is a good farmer'
new_strs.split()         #prints ['Johnny', 'Appleseed', 'is', 'a', 'good', 'farmer']

Better solution:

使用regex：

>>> import re
>>> from string import punctuation
>>> strs = "Johnny.Appleseed!is:a*good&farmer"
>>> r = re.compile(r'[{}]'.format(punctuation))
>>> new_strs = r.sub(' ',strs)
>>> len(new_strs.split())
6
#using `re.split`:
>>> strs = "Johnny.Appleseed!is:a*good&farmer"
>>> re.split(r'[^0-9A-Za-z]+',strs)
['Johnny', 'Appleseed', 'is', 'a', 'good', 'farmer']

Answer 2

这是一个不需要导入任何库的单行解决方案。 它用空格替换非字母数字字符（如标点符号），然后splits字符串。

灵感来自“Python strings split with multiple separators”

>>> s = 'Johnny.Appleseed!is:a*good&farmer'
>>> words = ''.join(c if c.isalnum() else ' ' for c in s).split()
>>> words
['Johnny', 'Appleseed', 'is', 'a', 'good', 'farmer']
>>> len(words)
6

Answer 3

试试这个：它使用re解析word_list，然后创建一个单词词典：appearances

import re
word_list = re.findall(r"[\w']+", string)
print {word:word_list.count(word) for word in word_list}

Answer 4

如何使用收藏品中的Counter？

import re
from collections import Counter

words = re.findall(r'\w+', string)
print (Counter(words))

Answer 5

for ltr in ('!', '.', ...) # insert rest of punctuation
     stringss = strings.replace(ltr, ' ')
return len(stringss.split(' '))

Answer 6

我知道这是一个古老的问题，但是......这个怎么样？

string = "If Johnny.Appleseed!is:a*good&farmer"

a = ["*",":",".","!",",","&"," "]
new_string = ""

for i in string:
   if i not in a:
      new_string += i
   else:
      new_string = new_string  + " "

print(len(new_string.split(" ")))

Answer 7

#Write a python script to count words in a given string.
 s=str(input("Enter a string: "))
 words=s.split()
 count=0
  for word in words:
      count+=1

  print(f"total number of words in the string is : {count}")