C++ 中的 ASCII 艺术

Question

我试图将 ASCII art 放入 C++ 程序中，并通过手动打印每一行来实现，但结果与 ASCII art 完全不同。就像：

出现这种情况是因为提示无法识别字符还是我没有正确操作？

这是我正在尝试做的 ASCII 艺术：

_____/\\\\\\\\\________/\\\\\\\\\\\__________/\\\\\\\\\__/\\\\\\\\\\\__/\\\\\\\\\\\_        
 ___/\\\\\\\\\\\\\____/\\\/////////\\\_____/\\\////////__\/////\\\///__\/////\\\///__       
  __/\\\/////////\\\__\//\\\______\///____/\\\/_______________\/\\\_________\/\\\_____      
   _\/\\\_______\/\\\___\////\\\__________/\\\_________________\/\\\_________\/\\\_____     
    _\/\\\\\\\\\\\\\\\______\////\\\______\/\\\_________________\/\\\_________\/\\\_____    
     _\/\\\/////////\\\_________\////\\\___\//\\\________________\/\\\_________\/\\\_____   
      _\/\\\_______\/\\\__/\\\______\//\\\___\///\\\______________\/\\\_________\/\\\_____  
       _\/\\\_______\/\\\_\///\\\\\\\\\\\/______\////\\\\\\\\\__/\\\\\\\\\\\__/\\\\\\\\\\\_ 
        _\///________\///____\///////////___________\/////////__\///////////__\///////////__

代码：

cout << "_____/\\\\\\\\\________/\\\\\\\\\\\__________/\\\\\\\\\__/\\\\\\\\\\\__/\\\\\\\\\\\_        \n";
cout << " ___/\\\\\\\\\\\\\____/\\\/////////\\\_____/\\\////////__\/////\\\///__\/////\\\///__       \n";
cout << "  __/\\\/////////\\\__\//\\\______\///____/\\\/_______________\/\\\_________\/\\\_____      \n";
cout << "  _\/\\\_______\/\\\___\////\\\__________/\\\_________________\/\\\_________\/\\\_____     \n";
cout << "    _\/\\\\\\\\\\\\\\\______\////\\\______\/\\\_________________\/\\\_________\/\\\_____    \n";
cout << "    _\/\\\/////////\\\_________\////\\\___\//\\\________________\/\\\_________\/\\\_____   \n";
cout << "      _\/\\\_______\/\\\__/\\\______\//\\\___\///\\\______________\/\\\_________\/\\\_____  \n";
cout << "       _\///________\///____\///////////___________\/////////__\///////////__\///////////__\n";

Answer 1

转义序列被解释为单个特殊字符或其他字符，因此输出很奇怪。例如，"\\"

 表示 

'\'

。

您可以使用原始字符串文字：

#include <iostream>

int main()
{
    std::cout << R"(
_____/\\\\\\\\\________/\\\\\\\\\\\__________/\\\\\\\\\__/\\\\\\\\\\\__/\\\\\\\\\\\_        
 ___/\\\\\\\\\\\\\____/\\\/////////\\\_____/\\\////////__\/////\\\///__\/////\\\///__       
  __/\\\/////////\\\__\//\\\______\///____/\\\/_______________\/\\\_________\/\\\_____      
   _\/\\\_______\/\\\___\////\\\__________/\\\_________________\/\\\_________\/\\\_____     
    _\/\\\\\\\\\\\\\\\______\////\\\______\/\\\_________________\/\\\_________\/\\\_____    
     _\/\\\/////////\\\_________\////\\\___\//\\\________________\/\\\_________\/\\\_____   
      _\/\\\_______\/\\\__/\\\______\//\\\___\///\\\______________\/\\\_________\/\\\_____  
       _\/\\\_______\/\\\_\///\\\\\\\\\\\/______\////\\\\\\\\\__/\\\\\\\\\\\__/\\\\\\\\\\\_ 
        _\///________\///____\///////////___________\/////////__\///////////__\///////////__        
)" << '\n';

    return 0;
}

现场演示

Answer 2

它不起作用，因为要显示 1 个反斜杠()，我们需要输入 2，即 (\)。如果您需要的话，这是代码：

#include <iostream> 使用命名空间 std；

int main() { cout

<<"/\\\\\/\\\\\\/\\\\\/\\\\\\/\\\\\ \ ” "<<
/\\\\\\\/\\/////////\\/\\/////////\//////\/////\ \///\/////\\/// ” " <<
/\\/////////\\\//\\\////\\/\/\\ \/\\ ” " <<
\/\\\/\\\////\\__________/\\\/\\\/\ \ ” " <<
\/\\\\\\\\\////\\\/\\\/\\ \/\\ ” " <<
\/\\/////////\\\////\\\//\\_______\/\\ \/\\ ” " <<
\/\\\/\\/\\\//\\\///\\\/\\ \/\\ ” " <<
\/\\\/\\\///\\\\\\/\////\\\\\/\\\\\_ /\\\\\\ “\///________\///<< " \///////////_______\/////////\////////// //\//////////// ”;

return 0; }