一个查询中另一个关系表的总和减去

Question

我有两个表，一个表称为出勤率，另一个表名为Timeslices，我试图获取当前一周的总从Timeslices中减去的出勤时间 Doctrine。我必须得到这些行，但是我必须对查询中的每一行进行求和和减去，但是我需要学习在一个查询中做到这一点。

这是出勤表的结构：

SELECT * FROM attendance;
+----+---------+---------------------+--------+---------------------+---------------------+
| id | user_id | day                 | status | check_in            | check_out           |
+----+---------+---------------------+--------+---------------------+---------------------+
|  1 |       1 | 2019-12-18 00:00:00 | end    | 2019-12-18 09:52:00 | 2019-12-18 23:37:02 |
|  2 |       1 | 2019-12-19 00:00:00 | end    | 2019-12-19 12:12:00 | 2019-12-19 21:05:00 |
+----+---------+---------------------+--------+---------------------+---------------------+

Timeslice表格：

SELECT * FROM timeslice;
+----+---------------+-------------------------------------+---------------------+---------------------+---------------------+
| id | attendance_id | title                               | day                 | start_at            | stopped_at          |
+----+---------------+-------------------------------------+---------------------+---------------------+---------------------+
| 20 |             1 | Sacar al perro, ducharme y vestirme | 2019-12-18 00:00:00 | 2019-12-18 15:57:50 | 2019-12-18 12:15:36 |
| 21 |             1 | Dormir                              | 2019-12-18 00:00:00 | 2019-12-18 18:44:30 | 2019-12-18 16:16:44 |
| 22 |             1 | Descansar                           | 2019-12-18 00:00:00 | 2019-12-18 23:04:53 | 2019-12-18 20:56:29 |
| 23 |             2 | Comer                               | 2019-12-19 00:00:00 | 2019-12-19 16:03:00 | 2019-12-19 15:37:00 |
| 24 |             2 | Comer                               | 2019-12-19 00:00:00 | 2019-12-19 16:55:00 | 2019-12-19 16:17:00 |
| 25 |             2 | ducharme                            | 2019-12-19 00:00:00 | 2019-12-19 19:58:00 | 2019-12-19 17:20:00 |
+----+---------------+-------------------------------------+---------------------+---------------------+---------------------+

这是我当前的query，在其中获得结果，但是随后我必须从查询中计算出以获得所需的结果和SQLFiddle：http://sqlfiddle.com/#!9/646be/3

SELECT SUM(TIME_TO_SEC(TIMEDIFF(a.check_out, a.check_in))) AS secondsAttendance
     , ( SELECT SUM(TIME_TO_SEC(TIMEDIFF(t.start_at, t.stopped_at))) 
           FROM timeslice t 
          WHERE t.attendance_id = a.id
       ) secondsPauses 
  FROM attendance a 
 GROUP 
    BY a.id

我之前说过的需要能够在同一查询中完成它，而不必使用PHP和Doctrine

Answer 1

不确定目标是什么（在示例中，您的时间片表上有一些数据，在'stopped_at'之后是'start_at'）

INSERT INTO `timeslice` (`id`, `attendance_id`, `title`, `day`, `start_at`, `stopped_at`) 
VALUES(23, 2, 'Comer', '2019-12-19 00:00:00', '2019-12-19 16:03:00', '2019-12-19 15:37:00'),

假设这只是一个错误，也许您正在寻找类似的东西？
SELECT 
   a.id, 
   SUM(TIME_TO_SEC(TIMEDIFF(a.check_out, a.check_in))) AS secondsAttendance, 
   SUM(TIME_TO_SEC(TIMEDIFF(t.start_at, t.stopped_at))) AS secondsPauses, 
   SUM(TIME_TO_SEC(TIMEDIFF(a.check_out, a.check_in))) - SUM(TIME_TO_SEC(TIMEDIFF(t.start_at, t.stopped_at))) AS actualSecondaAttendace -- Get your actual value
 FROM attendance a 
 LEFT JOIN timeslice t ON t.attendance_id = a.id
 WHERE yearweek(DATE(a.check_in), 1) = yearweek(curdate(), 1) -- filter by current week (assuming that checkin and checkout is on same day)
 GROUP BY a.id

这是我从您的数据中得到的结果：
+----+-------------------+---------------------+------------------------+
| id | secondsAttendance | secondsPauses       | actualSecondaAttendace |
+----+-------------------+---------------------+------------------------+
| 1  | 148506            | 29904               | 118602                 |
+----+-------------------+---------------------+------------------------+
| 2  | 95940             | 13320               | 82620                  |
+----+-------------------+---------------------+------------------------+

或者如果您只想为当前一周估值：
SELECT 
   SUM(TIME_TO_SEC(TIMEDIFF(a.check_out, a.check_in))) - SUM(TIME_TO_SEC(TIMEDIFF(t.start_at, t.stopped_at))) AS actualSecondaAttendace 
 FROM attendance a 
 LEFT JOIN timeslice t ON t.attendance_id = a.id
 WHERE yearweek(DATE(a.check_in), 1) = yearweek(curdate(), 1)

这是我从您的数据中得到的结果：
+------------------------+
| actualSecondaAttendace |
+------------------------+
| 201222                 |
+------------------------+