Google App 脚本递归循环不触发prompt.getResponseText()

Question

我编写了以下脚本来识别两个文件之间不匹配的名称。这对于第一个循环来说工作得非常好，并且在第二个循环中它完全可以很好地达到 var 提示，但是每当我尝试完成工作表上的提示时，它似乎什么也不做，只是停在那里。这不是因为输入，因为如果我第一次输入该输入，它就会顺利进行。我一定错过了一些关于为什么这不能正确循环的事情。任何帮助将不胜感激

function onEdit(e) {
    startPoint();
    
}

function startPoint(){
  var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("README");
    var cell = "N5";
    var difference = sheet.getRange(cell).getValue().toFixed(2);

    if (difference > 0){
      yesDifference(difference);
    }else noDifference(difference);
}

function yesDifference(num){
  const ui = SpreadsheetApp.getUi()
    const result = ui.alert(
     'There is a difference of: ' + 
     num
      + '\nWould you like to solve the issue',
      ui.ButtonSet.YES_NO)
    if (result == ui.Button.YES){
      findDifference(num);
    }else{
      return
    }
}

function noDifference(num){
  const ui = SpreadsheetApp.getUi()
    const result = ui.alert(
     'Tips are matching!');
    return
}

function findDifference(num){
  const ui = SpreadsheetApp.getUi();
  var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("README");
  var missingNames = sheet.getRange("Z3:Z20").getValues();
  for(var i = 0; i < missingNames.length; i++){
      var person = missingNames[i].toString();
      if(person.length > 1){
        const result = ui.alert(
          'I am not able to match:\n' + person + '\nbetween Harri and R365 would you like to try and find them?',
          ui.ButtonSet.YES_NO);
        if(result == ui.Button.YES){
          findNameMatch(person);
        }
      }
  }
    return
}

function findNameMatch(name){
  const ui = SpreadsheetApp.getUi();

  var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("README");

  var allNames = sheet.getRange("A2:A100").getValues();
  var filteredNames = [];

  for(var i = 0; i < allNames.length; i++){
    var person = allNames[i].toString();
    if(!(person.length > 1)){
      i = allNames.length;
    }else{
      if(!(filteredNames.includes(person))){
        filteredNames.push(person);
      } 
    }
  }

  var prompt = ui.prompt('Out of the following names:\n\n\n' + filteredNames.join('\r\n') + "\n\n\nPlease enter below which name is supposed to be " + name);

  var fullName = prompt.getResponseText().toString();

  var resp = ui.alert(fullName);

  var firstName = fullName.substring(0, fullName.indexOf(' '));
  var lastName = fullName.substring(fullName.indexOf(' ') + 1);

  var originalFirst = name.substring(0, name.indexOf(' '));
  var originalLast = name.substring(fullName.indexOf(' ') + 1);

  var names = ui.alert(
    'First Name: ' + firstName + "\nLast Name: " + lastName
  )

  changeName(originalFirst, firstName, originalLast, lastName);
  startPoint();
}

function changeName(oldF, correctF, oldL, correctL){
  var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("365");
  var allFNames = sheet.getRange("A2:A100").getValues();
  var allLNames = sheet.getRange("B2:B100").getValues();

  for(var i = 0; i < allFNames.length; i++){
    var name = allFNames[i].toString();
    var lastName = allLNames[i].toString();
    if(!(name.length > 1)){
      i = allFNames.length;
    }else{
      if((name === oldF) &&(lastName === oldL)){
        var newFirst = "A" + (i + 2);
        var newLast = "B" + (i + 2);

        var newFNames = sheet.getRange(newFirst).setValue(correctF);
        var newLNames = sheet.getRange(newLast).setValue(correctL);

        const ui = SpreadsheetApp.getUi();
        const result = ui.alert(
        'The names have been changed at ' + newFirst + ", and " + newLast + " to " + correctF + ", and " + correctL);
        i = allFNames.length;
      }
    }
  }
  return
}

我创建了一个电子表格，其中包含最少的数据来重现问题。在 R365 表上，如果您编辑其中一个名称，它应该以相同的方式触发该功能

https://docs.google.com/spreadsheets/d/1uLOghTaxPURScAsAvwhyPZpmaVh5P7o7E4c88gwn9a4/edit?gid=160981461#gid=160981461

Answer 1

您想要更新与现有数据不匹配的客户姓名，但您的循环不起作用。

考虑这个答案：

差异

• 'onEdit(e)` 是一个简单触发器，正在超时最大执行时间。

  • 将函数名称从

    onEdit(e)

    更改为其他名称，例如

    updateNames(e)

  • 为新函数名称创建可安装的

    onEdit

    触发器。
  • 如果不更改函数名称，则存在该函数将执行两次的风险 - 一次作为可安装触发器，一次作为简单触发器。结果令人困惑并引发错误。

• 利用事件对象。

  • 在

    Logger.log(JSON.stringify(e))

    之后立即插入

    updateNames(e)

    。
    • 这将显示可用的事件对象
  • 更改

    startPoint(e)

    和

    function startPoint(e){

• 在

  startpoint(e)

  中包括对工作表、列和行的测试，例如：
  

  if (e.range.getSheet().getName() == "README" && e.range.rowStart == 5 && e.range.columnStart == 14 ){

  • 这将确保可以在不调用整个函数的情况下进行不相关的编辑

• 错误

  var originalLast = name.substring(fullName.indexOf(' ') + 1);

  • 更改为

    var originalLast = name.substring(name.indexOf(' ') + 1);

• 从

  startPoint();

   最后一行删除 

  function findNameMatch(name){
  • 循环依赖于

    for(var i = 0; i < missingNames.length; i++){

     中的 

    function findDifference
  • 返回到

    startPoint()

    会重新启动整个函数，而不是让“for”循环发挥作用。

• 包含许多

  Logger

  语句来跟踪变量的值和例程的进度。这些缓慢的处理和 OP 可能希望显示那些在任何时间点看起来有帮助的内容。

• 尚不清楚“365”表中 M 列的值是否应更新为“差异”。

---

function updateNames(e) {
  // Logger.log(JSON.stringify(e)) // DEBUG
  startPoint(e);
    
}

function startPoint(e){
  // test for edited sheet and column and row
  if (e.range.getSheet().getName() == "README" && e.range.rowStart == 5 && e.range.columnStart == 14 ){ // cell 'N5"
    // edit is in correct place, continue processing 
    // Logger.log("DEBUG: edit was in N5 on Readme - continue processing")
    var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("README");
    var cell = "N5";
    var difference = sheet.getRange(cell).getValue().toFixed(2);
    if (difference > 0){
      yesDifference(difference);
    }else{
       noDifference(difference);
    }
  }
  else{
    // edit is NOT in correct place, stop processing 
    // Logger.log("DEBUG: edit was NOT N5 on Readme - stop processing")
    return
  }
}

function yesDifference(num){
  const ui = SpreadsheetApp.getUi()
    const result = ui.alert(
     'There is a difference of: ' + 
     num
      + '\nWould you like to solve the issue',
      ui.ButtonSet.YES_NO)
    if (result == ui.Button.YES){
      // solve the difference
      // Logger.log("DEBUG: solve the difference")
      findDifference(num);
    }else{
      // do nothing
      // Logger.log("DEBUG: Do nothing")
      return
    }
}

function noDifference(num){
  const ui = SpreadsheetApp.getUi()
    const result = ui.alert(
     'Tips are matching!');
    return
}

function findDifference(num){
  const ui = SpreadsheetApp.getUi();
  var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("README");
  var missingNames = sheet.getRange("Z3:Z20").getValues();
  for(var i = 0; i < missingNames.length; i++){
      var person = missingNames[i].toString();
      if(person.length > 1){
        const result = ui.alert(
          'I am not able to match:\n' + person + '\nbetween Harri and R365 would you like to try and find them?',
          ui.ButtonSet.YES_NO);
        if(result == ui.Button.YES){
          // Logger.log("DEBUG: the name of the person is "+person)
          findNameMatch(person);
        }
      }
  }
    return
}

function findNameMatch(name){
  const ui = SpreadsheetApp.getUi();

  var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("README");

  var allNames = sheet.getRange("A2:A100").getValues();
  var filteredNames = [];

  for(var i = 0; i < allNames.length; i++){
    var person = allNames[i].toString();
    if(!(person.length > 1)){
      i = allNames.length;
    }else{
      if(!(filteredNames.includes(person))){
        // Logger.log("DEBUG: filtered names doesn't include "+person+", so person added to filtered names")
        filteredNames.push(person);
      } 
    }
  }

  var prompt = ui.prompt('Out of the following names:\n\n\n' + filteredNames.join('\r\n') + "\n\n\nPlease enter below which name is supposed to be " + name);

  var fullName = prompt.getResponseText().toString();

  var resp = ui.alert(fullName);
  // Logger.log("DEBUG: name chosen for findNameMatch = "+fullName)
  var firstName = fullName.substring(0, fullName.indexOf(' '));
  var lastName = fullName.substring(fullName.indexOf(' ') + 1);

  var originalFirst = name.substring(0, name.indexOf(' '));
  var originalLast = name.substring(name.indexOf(' ') + 1);
  // Logger.log("DEBUG: findNameMatch: first name = "+firstName+", last name = "+lastName+", Original first  = "+originalFirst+", Original last = "+originalLast)
  var names = ui.alert(
    'First Name: ' + firstName + "\nLast Name: " + lastName
  )

  changeName(originalFirst, firstName, originalLast, lastName);
  
}

function changeName(oldF, correctF, oldL, correctL){
  // Logger.log("DEBUG: changename: oldF = "+oldF+", correct F = "+correctF+", oldL = "+oldL+", correct L = "+correctL)
  var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("365");
  var allFNames = sheet.getRange("A2:A100").getValues();
  var allLNames = sheet.getRange("B2:B100").getValues();

  for(var i = 0; i < allFNames.length; i++){
    var name = allFNames[i].toString();
    var lastName = allLNames[i].toString();
    // Logger.log("DEBUG: changeName: i:"+i+", name:"+name+", last name:"+lastName+", name length:"+name.length)
    if(!(name.length > 1)){
      i = allFNames.length;
    }else{
      if((name === oldF) &&(lastName === oldL)){
        // Logger.log("DEBUG: name <> old F and last name <> oldL")
        var newFirst = "A" + (i + 2);
        var newLast = "B" + (i + 2);
        // Logger.log("DEBUG: cells: newFirst:"+newFirst+", newlast:"+newLast)
        var newFNames = sheet.getRange(newFirst).setValue(correctF);
        var newLNames = sheet.getRange(newLast).setValue(correctL);
        // Logger.log("DEBUG: Updated newfirst and newlast with correctF and correctL")
        const ui = SpreadsheetApp.getUi();
        const result = ui.alert(
        'The names have been changed at ' + newFirst + ", and " + newLast + " to " + correctF + ", and " + correctL);
        i = allFNames.length;
        // Logger.log("DEBUG: i is set to allFnames length: "+i)
      }else{
        // Logger.log("DEBUG: if unsuccessful")
      }
    }
  }
  return
}

---

样本数据 - 之前的“Harri”表

样本数据 - 表“365：之前

示例数据 - 第 2 人

示例数据 - 第 4 人