URL请求中没有发送页面。获得成功,但结果空洞

问题描述 投票:-1回答:1

我的Api的尾部有Constants.getliked =“ get-liked-story?page = 1”。我正在通过alamofire请求,但没有得到响应。如何发送包含以下内容的页码?和=符号。

let url : String = Constants.wevlrBaseUrl + Constants.privateLink + Constants.getliked

       //let sv = UIViewController.displaySpinner(onView: view)
        let userToken = UserDefaultValues.authToken
        let headers: HTTPHeaders = ["Authorization": "Bearer " + userToken!]
        let parameters: Parameters = [
            "page": "1" ]
        Alamofire.request(url, method: .get, parameters: parameters,headers:headers).responseJSON { response in

            print("request-",response.request!)
            print("response-",response.response!)
            print("data-",response.data!)
            print("result-",response.result)

            debugPrint(response)

            if let JSON = response.result.value {
                print("json: \(JSON)")
            }
        }
ios swift request alamofire
1个回答
0
投票

假设此值用于常量中的变量

let wevlrBaseUrl =  "https://stackoverflow.com"
let privateLink =  "/questions"
let getliked =  "/get-liked-story?page=1"

然后仅将Alamofire请求方法与url和headers参数一起使用

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