例如:
struct Foo<'a> { bar: &'a str }
fn main() {
let foo_instance = Foo { bar: "bar" };
let some_vector: Vec<&Foo> = vec![&foo_instance];
assert!(*some_vector[0] == foo_instance);
}
foo_instance
是否引用与*some_vector[0]
相同的实例,但我不能这样做......有可能吗?
有功能ptr::eq
:
use std::ptr;
struct Foo<'a> {
bar: &'a str,
}
fn main() {
let foo_instance = Foo { bar: "bar" };
let some_vector: Vec<&Foo> = vec![&foo_instance];
assert!(ptr::eq(some_vector[0], &foo_instance));
}
在Rust 1.17.0中稳定之前,您可以对*const T
执行强制转换:
assert!(some_vector[0] as *const Foo == &foo_instance as *const Foo);
它将检查引用是否指向内存中的相同位置。