将React Native RCTRootView退回给本机ViewController

Question

我正在创建一个将react-native与现有Swift应用集成的应用。

我研究过类似的问题：

• React-Native: Dismiss/Exit React-Native View back to Native
• How can I go back to native view controller from react-native page?

同时遵循不同的教程：

• React Native calling class methods on native Swift
• Swift in React Native the ultimate guide
• React Native tutorial integrating in an existing app *

和官方docs

问题是：所有这些都已过时（但是文档）。他们中的大多数使用旧版Navigation，而不是Stack Navigator。其中一篇教程（带星号的教程）展示了如何使用应用程序的rootTag将React Native应用程序撤回本机应用程序，但是同样，这是通过旧版Navigation完成的。

[如果尝试执行相同的操作，则无法从我的应用程序中看到props。

我有一个情节提要，里面有一个Button，单击后将其称为UIViewController：

ButtonController

import Foundation
import UIKit
import React

class ButtonController: UIViewController  {
    @IBOutlet weak var button: UIButton!

    @IBAction func buttonClicked(_ sender: Any) {
        let data:[String : String] = ["onNavigationStateChange": "{handleNavigationChange}",
                                      "uriPrefix":"/app"];
        let rootView = MixerReactModule.sharedInstance.viewForModule("ReactNativeApp", initialProperties: data)

        let viewController = UIViewController()
        viewController.view = rootView
        self.present(viewController, animated: true, completion: nil)
    }
}

并且当我启动应用程序时，我可以看到此：

2019-10-23 10:29:30.021 [info][tid:com.facebook.react.JavaScript] Running "ReactNativeApp" with {"rootTag":1,"initialProps":{"uriPrefix":"/app","onNavigationStateChange":"{handleNavigationChange}"}}

但是当我尝试访问React Native代码上的this.props属性时，我得到了undefined。

index.js

import HomeScreen from './components/HomeScreen'
import {AppRegistry} from 'react-native';
import {createAppContainer} from 'react-navigation';
import {createStackNavigator} from 'react-navigation-stack';

const MainNavigator = createStackNavigator({
  Home: {screen: HomeScreen}
}, {
  initialRouteName: 'Home'
})

const NavigationApp = createAppContainer(MainNavigator);

AppRegistry.registerComponent('ReactNativeApp', () => NavigationApp)

console.log("NANANA1", this)
console.log("NANANA2", this.routeName)
console.log("NANANA3", MainNavigator)
console.log("NANANA4", MainNavigator.props)
console.log("NANANA5", NavigationApp)
console.log("NANANA6", NavigationApp.props)

export default NavigationApp

HomeScreen.js

import React from 'react';
import {Text, View, Button, NativeModules} from 'react-native';

var RNBridge = NativeModules.RNBridge;

export default class HomeScreen extends React.Component {
    static navigationOptions = {
      headerTitle: () => (
        <Text>'Welcome'</Text>
      ),
      headerLeft: () => (
        <Button title="Dismiss" onPress={() => {
          console.log("WOLOLO: ", RNBridge)
          console.log("ROGAN: ", this._reactInternalFiber.tag)
          RNBridge.dismissPresentedViewController(this._reactInternalFiber.tag)
          // RNBridge.dismissPresentedViewController(1)
        }}/>
      )
    };
    render() {
      console.log('KIKIKI', this._reactInternalFiber.tag)
      console.log("MMMMMMM: ", this.props)
      return (
        <View style={{ flex: 1, alignItems: 'center', justifyContent: 'center' }}>
          <Text>Home Screen</Text>
        </View>
      );
    }
}

这些是我在RN中用于生成视图的2个文件。我已经尝试了很多方法来获取rootTag值，并且似乎唯一提供此值的是（XCode上的tag和rootTag相同（1））

this._reactInternalFiber.tag

但是我不知道如何将这些值发送到我的headerLeft方法以使用相同的标签，因此当我按下Dismiss按钮时，它将调用dismissPresentedViewController的Swift代码。

如何有效地撤消我的风险投资？还是至少让rootTag从Swift传递到我的headerLeft()方法？

我正在使用这些版本的react-native：

react-native-cli: 2.0.1
react-native: 0.61.2

Answer 1

如果您希望解散从RN View中显示的本机swift view控制器，则>]

self.dismiss(animated: true, completion: nil)
我如下所示提供了快速视图控制器

 let modelVC = ModelViewController()  <-- sub class of UIViewController

 DispatchQueue.main.async {
   let navController = UINavigationController(rootViewController: modelVC)
   navController.modalPresentationStyle = .fullScreen
   let topController = UIApplication.topMostViewController()
   topController?.present(navController, animated: true, completion: nil)
 }
我在UIApplication上进行了扩展，以找出上面使用的最顶级的视图控制器

extension UIApplication {

  class func topMostViewController(controller: UIViewController? = UIApplication.shared.keyWindow?.rootViewController) -> UIViewController? {

    if let navigationController = controller as? UINavigationController {
      return topMostViewController(controller: navigationController.visibleViewController)
    }

    if let tabController = controller as? UITabBarController {
      if let selected = tabController.selectedViewController {
        return topMostViewController(controller: selected)
      }
    }

    if let presented = controller?.presentedViewController {
      return topMostViewController(controller: presented)
    }

    return controller
  }
}