无法从EasyPHP服务器将数据输入到myPHPAdmin中

Question

我正在尝试将登录数据输入到myPHPAdmin数据库中，但是似乎没有任何数据输入。

<?php 

require_once "dbInfo.inc.php";

$firstName = $_POST['firstNameTextBox'];
$lastName = $_POST['lastNameTextBox'];
$phoneNum = $_POST['teleNumbBox'];
$email = $_POST['emailBox'];
$SIN = $_POST['SINNumBox'];
$password = $_POST['passTextBox'];

    $conn = mysqli_connect($host, $username, $dbPassword);

    if($conn->connect_error){
        die("connection Failed: ". $conn->connect_error);
        $connErrMsg = $conn->connect_error;
    }
    $succConn = "Successfuly Connected";

    mysqli_select_db($conn, $database);

    $sqlQuery = "INSERT INTO employee VALUES('$firstName', '$lastName', '$phoneNum', '$email', 
'$SIN', '$password')";

    if (mysqli_query($conn, $sqlQuery)) {

    } else {
        echo "Person Could not be added: " . $sqlQuery . "<br>" . mysqli_error($conn);
    }

    mysqli_query($conn, $sqlQuery);

    $queryError =  mysql_error($sqlQuery);

    mysqli_close($conn);

    session_start();
    $_SESSION["firstName"] = $firstName;
    $_SESSION["lastName"] = $lastName;
    $_SESSION["teleNum"] = $phoneNum;
    $_SESSION["email"] = $email;
    $_SESSION["SINNum"] = $SIN;
    $_SESSION["password"] = $password;
    $_SESSION["queryError"] = $queryError;
    $_SESSION["connErrMsg"] = $connErrMsg;
    $_SESSION["succConn"] = $succConn;
    header("Location: ../ViewAllEmployees.php");
    exit();

?>

我知道表单中的数据是正确的，因为我已经回显了变量，并且我所有的错误消息一无所获。如果有人知道是什么原因导致我无法输入数据，请告诉我。

Answer 1

您将需要在phpMyAdmin目录中打开config.inc.php，并确保其设置如下：

$cfg['Servers'][$i]['user'] = 'root';
$cfg['Servers'][$i]['password'] = '';
$cfg['Servers'][$i]['AllowNoPassword'] = true;

请注意，'AllowNoPassword'必须设置为true