我正在使用共享库在我的C ++应用程序中实现Matlab的功能匹配算法。问题是尽管我将四个参数传递给函数,但我仅获得一个参数的值。
Matlab函数:
[c, d, e, f] = fm_test("C:\0.jpg", "C:\1.jpg");
function [FSC_1, FSC_2, NBCS_1, NBCS_2] = fm_test(path_im1, path_im2)
...
% Performed feature matching - output are 4 matrices with format n x 2 single
FSC_1 = matchedPoints1(inliersIndex, :);
FSC_2 = matchedPoints2(inliersIndex, :);
NBCS_1 = matchedPoints1(inliers_NBCS, :);
NBCS_2 = matchedPoints2(inliers_NBCS, :);
end
我正在使用库编译器为C ++创建共享库并调用该函数:
mclmcrInitialize();
//const char *args[] = { "-nojvm" };
//const int count = sizeof(args) / sizeof(args[0]);
if (!mclInitializeApplication(NULL, 0)) {
std::cerr << "Could not initialize the application properly" << std::endl;
return -1;
}
if (!fm_testInitialize()) {
std::cerr << "Could not initialize the library properly" << std::endl;
return -1;
}
else {
try {
for (size_t i = 0; i < cameras.size() - 1; ++i){
mwArray FSC_1, FSC_2, NBCS_1, NBCS_2;
mwArray path_1 = cameras[i].image_path.c_str();
mwArray path_2 = cameras[i+1].image_path.c_str();
fm_test(1, FSC_1, FSC_2, NBCS_1, NBCS_2, path_1, path_2);
// Convert mwArray to vector<double>
std::cout << " Printing sizes of mwArray" << std::endl;
std::cout << FSC_1.NumberOfElements() << std::endl;
std::cout << FSC_2.NumberOfElements() << std::endl;
std::cout << NBCS_1.NumberOfElements() << std::endl;
std::cout << NBCS_2.NumberOfElements() << std::endl;
}
}
catch (const mwException& e) {
std::cerr << e.what() << std::endl;
return -2;
}
catch (...) {
std::cerr << "Unexpected error thrown" << std::endl;
return -3;
}
fm_testTerminate();
}
结果例如:
Printing sizes of mwArray
100
0
0
0
是否可以将多个参数传递给函数?我是否需要更具体地定义mwArray
?
与Matlab网站上的示例相反,我需要向函数传递不同的第一个参数。该函数定义为:extern LIB_fm_test_CPP_API void MW_CALL_CONV fm_test(int nargout, mwArray& FSC_1, mwArray& FSC_2, mwArray& NBCS_1, mwArray& NBCS_2, const mwArray& path_im1, const mwArray& path_im2);
第一个参数必须更改为输出的参数数量(在我的情况下为4)。正确的函数调用是:fm_test(4, FSC_1, FSC_2, NBCS_1, NBCS_2, path_1, path_2);