防止运行脚本或禁用按钮-tkinter

Question

我确定已经问过这个问题，我遇到了一些解决方案，但它们对我不起作用。如果用户给出的输入错误，我试图禁用我的tkinter gui中的按钮。

有两个输入字段，以秒为单位输入时间（分别为t1和t2）。完成输入后，用户单击“确认”按钮。我现在想做的是，如果没有正确输入时间，例如t1> t2，这将引发错误，并且代码将进入函数-time_error（）

一旦出现此错误，我想禁用'Go'按钮，以使脚本无法执行。

我正在尝试在time_error（）函数中禁用此“转到”按钮，但无法执行此操作。

以下是我的代码：

import tkinter as tk
from tkinter import ttk
import pdb

root = tk.Tk()
color = '#aeb3b0'

IntroCanvas = tk.Canvas(height = 200, width = 400, bg = color)
IntroCanvas.pack()

# time error funtion **********    THIS IS NOT WORKING FOR ME    **************
def time_error():
    GoButton = tk.Button(root, text="GO!", command=go,bg = 'green', fg = 'white', width=4)
    GoButton.place(relx=0.4, rely=0.5)
    GoButton = tk.Button.configure(root,state = 'DISABLED')

# ****************************************************************************

# t1_init ************ ENTER FIRST TIME VALUE IN SECONDS ****
def blank_t1entry(event):
    t1entry.delete(0, "end") 
    return None 
t1entry = tk.Entry(width = 13)
t1entry.place(relx = 0.1, rely = 0.25)
t1entry.insert(0,"From seconds")
t1entry.bind("<Button-1>", blank_t1entry)

# t2_init ************ ENTER SECOND TIME VALUE IN SECONDS ****
def blank_t2entry(event): 
    t2entry.delete(0, "end") 
    return None 
t2entry = tk.Entry(width = 12)
t2entry.place(relx = 0.4, rely = 0.25)
t2entry.insert(0,"To seconds")
t2entry.bind("<Button-1>", blank_t2entry)

# ****** GET THE ENTERED TIME VALUES AND COMPARE THEM TO SEE IF THEY ARE APPROPRIATE, ELSE THROW ERROR ***
def confirmTime_comp():                
    global t1_comp_init, t2_comp_init

    if not ((str.isnumeric(str(t1entry.get()).replace('.','')))|(t1entry.get()=='From seconds')):
        time_error()
    else:
        t1_comp_init = t1entry.get()

    if not ((str.isnumeric(str(t2entry.get()).replace('.','')))|(t2entry.get()=='To seconds')):
        time_error()
    else:
        t2_comp_init = t2entry.get()
    # below lines are for throwing an error if t1 > t2 or t1 < 0
    pdb.set_trace()
    if not ('seconds' in t1_comp_init):
        if not ('seconds' in t2_comp_init):
            if float(t1_comp_init) >= float(t2_comp_init):
                time_error()
            elif float(t1_comp_init) < 0:
                time_error()

# ****** BUTTON TO CONFIRM TIME ENTRIES *******************
CompTimeButton = tk.Button(root, text="Confirm", command=confirmTime_comp,bg = 'green', fg = 'white')
CompTimeButton.place(relx=0.6, rely=0.25)

def go():
    printLabel = tk.Label(root, text = 'Go Button Pressed')
    printLabel.place(relx = 0.35, rely = 0.75)


GoButton = tk.Button(root, text="GO!", command=go,bg = 'green', fg = 'white', width=4)
GoButton.place(relx=0.4, rely=0.5)

root.mainloop()

此外，如果用户输入不正确，还有其他更优雅的方法可以阻止运行脚本吗？

谢谢

R

Answer 1

我想我找到了一种禁用按钮的方法。它所需要的只是：

def time_error():
    GoButton['state'] = tk.DISABLED