试图创建一个称为向导的类的实例，并执行将其作为参数传递但不起作用的jump（）方法？

Question

这是我到目前为止所做的，但是当我编译代码时，它说找不到变量跳转。我写的不正确吗？

完整代码：

public class WizardController

{
   /**
    * instance variables
    */  

   private Wizard wizard1;
   private Wizard wizard2; 
   private int numOfRepeats;

   private static final int MIN_NUM_REPEATS = 1;
   private static final int MAX_NUM_REPEATS = 3;  

   public static final int LAST_CELL = 11;   

   /**
    * Constructor for objects of class WizardController.
    */
   public WizardController(Wizard aWizard1, Wizard aWizard2)
   {
      super();
      this.wizard1 = aWizard1;
      this.wizard2 = aWizard2; 
      this.numOfRepeats = 0;      
   }

   /* instance methods */  
   /**
    * Prompts the user for a number of action repeats
    * in the range 1 to 3 inclusive, and returns this number.
    */
   public int promptForNumOfRepeats()   
   {
     int moves;    
     moves = Integer.parseInt(OUDialog.request("Please enter the number of" 
         + " action repeats to be performed - between 1 and 3 (inclusive)"));

          try
     {
        moves = Integer.parseInt(OUDialog.request("Please enter the number of" 
          + " action repeats to be performed - between 1 and 3 (inclusive)"));
     }

    /**
    * Returns true if the argument is in the range 1 to 3 (inclusive),
    * otherwise false.
    */
   public boolean isValidNumOfRepeats(int aNumber)
   {
      return ((aNumber >= WizardController.MIN_NUM_REPEATS)
      && (aNumber <= WizardController.MAX_NUM_REPEATS));
   }   

   /**
    * Repeatedly prompts the user for a number of repeats of the moves, 
    * until they enter a valid input representing a number in the range 1 to 3
    * inclusive, and  then returns this number.
    */    
   public int getNumOfRepeats()
   {
      int repeats = this.promptForNumOfRepeats();
      while (!this.isValidNumOfRepeats(repeats))
      {
         OUDialog.alert("That is not a valid number of game repeats");
         repeats = this.promptForNumOfRepeats();    
      }
      return repeats; 
   }   

     public void jump(Wizard wizard1)
      {
    wizard1.up();
    this.delay(1000);
    wizard1.down(); 
    Wizard w = new Wizard(jump); <<<< not working
    }

这是我到目前为止所做的，但是当我编译代码时，它说找不到变量跳转。我写的不正确吗？到目前为止，这是我所做的，但是在编译代码时却说找不到变量跳转。我写的不正确吗？

Answer 1

确实是您得到的错误是正确的。您正在尝试将名为jump的变量传递给Wizard对象的构造函数。

但是，跳转是一种接受向导的方法。因此，您可以在jump方法之外的某处编写以下代码（除非您尝试创建递归性）：

 public void jump(Wizard wizard1)
  {
wizard1.up();
this.delay(1000);
wizard1.down(); 

}

public void otherMethod() {
Wizard w = new Wizard();
this.jump(w); 
}