为什么 on_call firebase 函数返回内部异常

Question

firebase 本地模拟端：

initialize_app()

@https_fn.on_call( cors=options.CorsOptions(
        cors_origins="*",
        cors_methods=["get", "post", "options"],))
def validateEmail(req: https_fn.CallableRequest) -> Any :
    return {"text":{"valid:":"true"}}

Android 应用程序端。

    val func = Firebase.functions
    private fun validateEmail(str:String): Task<String> {
        val data = hashMapOf(
            "email" to str
        )
        return func.getHttpsCallable("validateEmail").call(data)
            .continueWith()
            {  task ->
                println("RAM_DBG" + task.result?.data.toString())
                task.result?.data as String

            }

    }

    override  fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)

        func.useEmulator("localhost", 5001)
        validateEmail("[email protected]")
            .addOnCompleteListener { task ->
                if (!task.isSuccessful)
                {
                    val e = task.exception
                    if(e is FirebaseFunctionsException)
                    {
                        println("RAM_DBG:" + e.code.toString() + e.details.toString())
                    }
                }
            }

这总是给出 FirebaseFunctionsException 和 code = INTERNAL。怎么了？ 两侧都有哪些仪器和记录可能？ 当使用如下的curl运行时

curl -H "Content-Type:application/json" -d @book.json -X POST http://127.0.0.1:5001/<app>/us-central1/validateEmail
{"result":{"text":{"valid":"true"}}}

期望返回“valid:”:“true”

Answer 1

键“valid:”可能会因为冒号而导致问题。将其更改为“有效”