C++ 中字符串和双精度数的异常处理错误

Question

我正在尝试编写一个关于土豆泥的程序，但我的异常处理无法正常工作。相反，我得到以下输出： 输出显示 if (DaysNumber < 7) output instead of the error message

我有以下代码（这是我的主文件；如果您也想查看这些文件，我在这个问题的底部有一个指向我的 GitHub 存储库的链接，其中包含其他文件）：

#include <iostream>
#include <iomanip>
#include <string>
#include <cstdlib>
#include <stdexcept>
#include "tatertot.h"

using namespace std;

int main() {
    int DaysNumber;
   
    // Asks the user how long it’s been since they ate tater tots
    cout << "How long has it been since you had some yummy tots?" << endl;
    cout << "Enter the number of days: " << endl;
    cin >> DaysNumber;

    // Handles invalid inputs
   try {
       // If it’s been a week (or more) since the user ate tater tots…
        if (DaysNumber >= 7) {
            cout << "Yay! I bet those tots were delicious. Here's a recipe to try next time you want to eat tater tots: " << endl;
            cout << "https://www.allrecipes.com/recipe/236749/tater-tots-nachos/";
            abort();
        }

        // If the user ate tater tots recently…
        else {
            cout << "It. Is. TATER TOT TIME!" << endl;
            cout << "Go enjoy some yummy tots!" << endl;
            cout << "https://www.allrecipes.com/recipe/236749/tater-tots-nachos/";
            abort();
        }

    }
    catch (string e) {
        cin.clear();
        cout << "I'm sorry, but your input is invalid. Could you please try again?" << endl;
        cin >> DaysNumber;
    }

    catch (double e) {
        cin.clear();
        cout << "I'm sorry, but your input is invalid. Could you please try again?" << endl;
        cin >> DaysNumber;
    }
    return 0;
};

我尝试过使用其他异常处理方法并在类文件和访问器-变异器文件中定义 DaysNumber，但无济于事。也许我在这里缺少一些东西？

哦，这是我的 GitHub 存储库的链接：https://github.com/NEE64/potate-repository

Answer 1

您的无效输入只会导致 0 被读入变量。没有什么会引发您试图捕获的异常。

喜欢，请查看 https://en.cppreference.com/w/cpp/io/basic_istream/operator_gtgt :

如果提取失败（例如，如果在需要数字的地方输入了字母），则将零写入值并设置失败位。