我有一个父屏幕,使用模式查看交易。我想在AddTrade屏幕中按下关闭按钮时关闭此模式。硬件后退按钮已禁用,但是可以模拟硬件按钮按下吗?我想在按下提交时关闭模式,但是两者都在不同的屏幕中。
//View Trade
render() {
const {
navigation,
} = this.props;
return (
<View style={{padding: 10}}>
<View style={{flexDirection: 'row', borderWidth: 2}}>
<View style={{flex: 1, flexDirection: 'column'}}>
<TextInput placeholder="City" />
</View>
<View style={{flex: 1, flexDirection: 'column'}}>
<TextInput placeholder="Pokemon" />
</View>
<Icon
name="search"
type="font-awesome"
iconStyle={{
color: '#e6f2fd',
backgroundColor: '#2096f3',
padding: 10,
marginVertical: '10%',
}}
onPress={() => {
console.log('search');
}}
/>
</View>
{this._makeCards()}
<TouchableOpacity
onPress={() => {
console.log('add');
// this.props.navigation.navigate('Add Trades')
this.setState({isModalVisible:!this.state.isModalVisible})
}}
style={{
position: 'absolute',
height: '10%',
width: '20%',
bottom: '8%',
right: '3%',
}}>
<View>
<Image source={require('../assets/images/float-add-icon.png')} />
</View>
</TouchableOpacity>
<Modal visible={this.state.isModalVisible} onRequestClose={()=>{this.setState({isModalVisible:!this.state.isModalVisible})}} style={{margin:0,flex: 1, alignItems: 'center', justifyContent: 'center'}}>
<AddTrades navigation={this.props.navigation}/>
</Modal>
</View>
);
}
//AddTrade
return (
<View>
<View style={[styles.app, {justifyContent: 'center'}]}>
<Picker
style={styles.picker}
selectedValue={this.state.WhatTheyGive}
onValueChange={(itemValue, itemIndex) =>
this.setState({WhatTheyGive: itemValue})
}>
{this.addPicker()}
</Picker>
<TextInput placeholder="Enter CP" style={styles.textInput} />
<TextInput placeholder="Enter city" style={styles.textInput} />
<Picker
style={styles.picker}
selectedValue={this.state.whatTheyWant}
onValueChange={(itemValue, itemIndex) =>
this.setState({whatTheyWant: itemValue})
}>
{this.addPicker()}
</Picker>
<View style={styles.button}>
// I want to hide modal when this is pressed.
<Button title="Submit" onPress={this._onSubmit} />
</View>
</View>
</View>
);
}
使父组件取决于状态。即
constructor(props) {
super(props);
this.state = {
childValue: false
} }
<View style={{backgroundColor:this.state.childValue?"red":"green"}}> //Parent View
<TouchableOpacity onPress={() => this.setState({childValue:true)}> //ChildrenView
<Text>Click Me</Text>
</TouchableOpacity>
</View>
只需创建一个方法来更改isModalVisible值。然后将该方法传递给您的<AddTrade callback={method} />
。
然后在子组件中,当按下Button时调用此回调方法。
您可以在此方法上使用renderProps
方法。
您的Modal
组件在render
方法中的某个位置呈现children
属性。不仅仅是渲染children
prop,还可以将其作为函数children(...)
调用并传递所需的任何参数(在您的情况下,传递Modal
的onRequestClose
函数)。
// somethere in the render method:
{children(props.onRequestClose)}
[之后,不要照原样渲染<AddTrades />
,而是传递一个表达式,该表达式是一个包含AddTrades
实例的函数(以onRequestClose
函数作为参数!)。轻松地将该函数传递给您的AddTrades
(以及其他模态子对象)。
<Modal visible={this.state.isModalVisible} onRequestClose={()=>{this.setState({isModalVisible:!this.state.isModalVisible})}}>
{(onRequestClose) => <AddTrades onRequestClose={onRequestClose} />}
</Modal>
最后,只需在props.onRequestClose
组件中调用AddTrades
。