无法在Xpath中找到值(元素)

问题描述 投票:1回答:2

即使网页中存在元素,也无法在xpath中找到元素。实际上代码既不会抛出异常也不会查找元素。

for c in range(sheet.ncols):
    for r in range(sheet.nrows):
        st = (sheet.cell_value(r, c))
        print(str(st))
        xpath1 = "//input[@value='Analyze' and contains(@onclick,'" + str(st) + "')]"
        #xpath = "//input[@value='Analyze'][.='" + st + "']"
        print(driver.title)
        print(len(driver.find_elements_by_xpath(xpath1)))
        if driver.find_elements_by_xpath(xpath1):
            print("loop")
            driver.find_element_by_xpath(xpath1).click()  # Here new window will open
            time.sleep(2)
            #Main_Window = driver.current_window_handle
            driver.switch_to.window(driver.window_handles[-1])
            driver.find_element_by_xpath('/html/body/table/tbody/tr[4]/td/table/tbody/tr[9]/td[3]/input').click()
            driver.close()
            driver.switch_to.window(driver.window_handles[-1])
            xpath2 = "//*[@id='create_button']"
            xpath3 = "//*[@id='update_button']"
            if check_exists_by_xpath(xpath2):
                driver.find_element_by_xpath(xpath2).click()
                driver.close()
                driver.switch_to.window(driver.window_handles[0])

            elif check_exists_by_xpath(xpath3):
                driver.close()
                driver.switch_to.window(driver.window_handles[0])
                continue

预期产量应为:

23 ST 1循环45 ST 1 6 ST 1 89 ST 1

但运行以上代码时得到以下输出:23 ST 1循环4 ST 0 56 ST 0 7 ST 0

代码有什么问题?

提前致谢。

python python-3.x selenium selenium-webdriver
2个回答
1
投票

只需切换到正确的窗口和框架。

      if check_exists_by_xpath(xpath2):
            driver.find_element_by_xpath(xpath2).click()

      #else not required as you are not using the xpath3 to click

      driver.close()
      driver.switch_to.window(driver.window_handles[0])
      driver.switch_to.frame(base_frame_locator/index)
      driver.switch_to.frame(child_frame_locator/index)
      continue

0
投票

我也希望看到您的HTML或获取指向网页的链接以检查xpath。但是根据你的输出,我认为很可能你没有切换到[0]不存在的窗口。您正在if语句中执行窗口开关,因此如果这些条件都不满足,则不会切换窗口。尝试从窗口切换出你的if,也许是这样的:

for c in range(sheet.ncols):
    for r in range(sheet.nrows):
        st = (sheet.cell_value(r, c))
        print(str(st))
        xpath1 = "//input[@value='Analyze' and contains(@onclick,'" + str(st) + "')]"
        #xpath = "//input[@value='Analyze'][.='" + st + "']"
        print(driver.title)
        print(len(driver.find_elements_by_xpath(xpath1)))
        if driver.find_elements_by_xpath(xpath1):
            print("loop")
            driver.find_element_by_xpath(xpath1).click()  # Here new window will open
            time.sleep(2)
            #Main_Window = driver.current_window_handle
            driver.switch_to.window(driver.window_handles[-1])
            driver.find_element_by_xpath('/html/body/table/tbody/tr[4]/td/table/tbody/tr[9]/td[3]/input').click()
            driver.close()
            driver.switch_to.window(driver.window_handles[-1])
            xpath2 = "//*[@id='create_button']"
            xpath3 = "//*[@id='update_button']"
            if check_exists_by_xpath(xpath2):
                driver.find_element_by_xpath(xpath2).click()
            driver.close()
            driver.switch_to.window(driver.window_handles[0])

我认为你甚至不需要你的第二个if语句,因为它只包含

driver.close()
driver.switch_to.window(driver.window_handles[0])
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