python tkinter - 当按下 Shift 和功能键，或者按下 Control 和功能键时检测箭头键

Question

这是先前问题的后续问题 ( python tkinter - 当按下备用键时检测箭头键 )

我还希望能够检测是否按下了功能键以及Shift键或控制键，同时按下了方向键之一（上、下、左、右）。

import tkinter

def on_key_press(event):

    if event.state & 0x0001: # shift key
        if event.keysym == 'Down':
            print("shift and down arrow")
        elif event.keysym == 'Up':
            print("shift and up arrow")
        elif event.keysym == 'Left':
            print("shift and left arrow")
        elif event.keysym == 'Right':
            print("shift and right arrow")
 
    elif event.state & 0x????:     # shift key and function key 0x????
        if event.keysym == 'Down':
            print("shift and function and down arrow")
        elif event.keysym == 'Up':
            print("shift and function  and up arrow")
        elif event.keysym == 'Left':
            print("shift and function and left arrow")
        elif event.keysym == 'Right':
            print("shift and function and right arrow")
 
    elif event.state & 0x0004: # control key
        if event.keysym == 'Down':
            print("control and down arrow")
        elif event.keysym == 'Up':    
            print("control and up arrow")
        elif event.keysym == 'Left':
            print("control and left arrow")
        elif event.keysym == 'Right':
            print("control and right arrow")

    elif event.state & 0x????:    # control key and function key 0x????
        if event.keysym == 'Down':
            print("control and function and down arrow")
        elif event.keysym == 'Up':
            print("control and function and up arrow")
        elif event.keysym == 'Left':
            print("control and function and left arrow")
        elif event.keysym == 'Right':
            print("control and function and right arrow")

    elif event.state & 0x20000: # alternate key
        if event.keysym == 'Down':
            print("alternate and down arrow")
        elif event.keysym == 'Up':
            print("alternate and up arrow")
        elif event.keysym == 'Left':
            print("alternate and left arrow")
        elif event.keysym == 'Right':
            print("alternate and right arrow")

我希望有一对 0x？？？面具将使这一切变得容易。

Answer 1

这些是来自 text.bind(Key, function) 的 event.state 值

大写锁定关闭

1. 262144 = 0 =“1000000000000000000” - 打开
2. 262145 = 1 =“1000000000000000001” - 移位
3. 262148 = 4 =“1000000000000000100”-ctrl
4. 262149 = 5 =“1000000000000000101”-shift+ctrl

大写锁定打开

1. 262146 = 2 =“1000000000000000010” - 打开
2. 262147 = 3 =“1000000000000000011” - 移位
3. 262150 = 6 =“1000000000000000110”-ctrl
4. 262151 = 7 = "1000000000000000111" - ctrl+shift

以下代码演示了事件行为和 event.state 值。

等效的二进制值可以使用按位测试。

此代码只是将 event.state 值分组到元组中进行测试并显示结果。

from tkinter import Tk, LabelFrame, Text

master = Tk()
frame = LabelFrame(master, text = "Report")
frame.grid(sticky = "nsew")
text = Text(frame, undo = 1)
text.grid(sticky = "nsew")

def react(event):
    if event.state in (5, 7, 262149, 262151):
        k = f"ctrl+shift keys {event.state}"
    elif event.state in (4, 6, 262148, 262150):
        k = f"ctrl key {event.state}"
    elif event.state in (1, 3, 262145, 262147):
        k = f"shift key {event.state}"
    elif event.state in (0, 2, 262144, 262146):
        k = f"open key {event.state}"
    else:
        k = f"?? {event.keysym} & {event.state} ??"
    result = f"{k} = {event.keysym}"
    frame['text'] = result
    print(result)

text.bind("<Key>", react)

text.focus_set()
master.mainloop()