Scanner Try Catch语句导致java.util.InputMismatchException

问题描述 投票:0回答:2

为什么我的代码会给我一个错误?如果用户输入了错误的号码,代码是否应该让我输入新的有效号码?似乎它不会让我将喜爱改为新值。我怎么能解决这个问题?

package RobB;

import java.util.Scanner;

public class FavoriteNum {

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        int[] num = new int[10];
        int favorite = 0;

        System.out.print("Enter your favorite number: ");
        try {
            favorite = scan.nextInt();
        }
        catch (Exception e) {
            System.out.println("Enter an integer!");
            System.out.print("Enter your favorite number: ");

            favorite = scan.nextInt();
        }

        for (int i = 0; i < 10; i++) {
            System.out.print("Enter a random number (" + Math.abs(((i + 1) - 10)) + " to go): ");
            num[i] = scan.nextInt();
        }
    }
}

控制台输出:

Enter your favorite number: 11.1

Enter an integer!

Exception in thread "main" Enter your favorite number: java.util.InputMismatchException
    at java.util.Scanner.throwFor(Unknown Source)
    at java.util.Scanner.next(Unknown Source)
    at java.util.Scanner.nextInt(Unknown Source)
    at java.util.Scanner.nextInt(Unknown Source)
    at RobB.FavoriteNum.main(FavoriteNum.java:21)
java error-handling try-catch
2个回答
0
投票

扫描catch子句中的输入似乎不是最好的主意。我建议使用do-while循环,允许离开此循环的条件可能是boolean标志,当您确认最终输入有效的Integer时,状态将被更改。您可能还想考虑使用ScannerhasNextInt()方法来检查是否提供了正确的输入,如果在您的情况下不是真的需要,则不会抛出任何异常。这是ronhash答案的一点变化,但使用do-while循环:

boolean validInput = false;
do {
    try {
        System.out.print("Enter your favourite number: ");
        favorite = scan.nextInt();
        validInput = true; }
    catch (Exception e) {
        System.out.println("Enter an integer!"); }
} while (!validInput)

编辑:我编辑了代码,因为前一个代码效率低且错误。


1
投票

这是一个带有while循环的替代方法:

boolean validInput = false;
while (!validInput) {
   try {
        System.out.print("Enter your favourite number: ");
        favorite = scan.nextInt();
        validInput = true;
    }
    catch (Exception e) {
        System.out.println("Enter an integer!");
    }
}
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