如何修复'FileNotFoundError:[Errno 2]在上传的文件代码中替换字符串时没有这样的文件或目录错误?

问题描述 投票:0回答:1

我正在尝试替换字符串并在Flask中转换上传文件的编码。我已经找到上传文件的代码,并且可以正常工作,但是我在替换字符串和转换编码时遇到问题。我已经检查了许多有关该问题的问题,但是可能由于我的英语水平不足而无法找到解决方案。

我想我无法获取通过Web表单上传的文件。我正在将文件上传到“ static / uploads”文件夹,并且可以在此处看到文件。我需要帮助来获取上载的文件,然后检测编码并替换字符并保存。

我正在Windows PC上使用python 3.7。

import os
from chardet import detect
from app import app
from flask import render_template, flash, redirect,  request
from werkzeug.utils import secure_filename

ALLOWED_EXTENSIONS = set(['txt', 'srt'])
target_format = 'UTF-8'
outputDir = 'static/coverted'


def allowed_file(filename):
    return '.' in filename and filename.rsplit('.', 1)[1].lower() in ALLOWED_EXTENSIONS


@app.route('/')
def upload_form():
    return render_template('index.html')



@app.route('/upload', methods=['POST'])
def upload_file():
    if request.method == 'POST':
        # check if the post request has the file part
        if 'file' not in request.files:
            flash('No file part')
            return redirect(request.url)
        file = request.files['file']
        if file.filename == '':
            flash('No file selected for uploading')
            return redirect(request.url)
        if file and allowed_file(file.filename):
            filename = secure_filename(file.filename)
            file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))

            with open(filename, 'rb') as f:
                raw_data = f.read()
            source_format = detect(raw_data)['encoding']

            with open(filename, 'rU', source_format) as sf, open(outputDir + '/' + filename, 'w',
                                                                  encoding='UTF-8') as tf:
                content = sf.read()
                replaced_content = content.replace('Ý', 'İ').replace('ý', 'ı').replace('þ', 'ş').replace('ð', 'ğ').replace('Þ', 'Ş')
                tf.write(replaced_content)
            return redirect('/')
    else:
        flash('Allowed file types are txt,srt')
        return redirect(request.url)

我得到的结果是:AttributeError:'FileNotFoundError:[Errno 2]没有这样的文件或目录:

python file flask python-3.7
1个回答
0
投票

确定,我已经设法替换了内容,然后在上传后将其保存到文件中。如果其他人需要,这里是代码。

import os
from chardet import detect
from app import app
from flask import render_template, flash, redirect, request, send_from_directory, url_for
from werkzeug.utils import secure_filename

ALLOWED_EXTENSIONS = set(['txt', 'srt'])
target_format = 'UTF-8'
outputDir = 'static/coverted'


def allowed_file(filename):
    return '.' in filename and filename.rsplit('.', 1)[1].lower() in ALLOWED_EXTENSIONS


@app.route('/')
def upload_form():
    return render_template('index.html')


@app.route('/upload', methods=['POST'])
def upload_file():
    if request.method == 'POST':
        # check if the post request has the file part
        if 'file' not in request.files:
            flash('No file part')
            return redirect(request.url)
        file = request.files['file']
        if file.filename == '':
            flash('No file selected for uploading')
            return redirect(request.url)
        if file and allowed_file(file.filename):
            filename = secure_filename(file.filename)
            file_path = os.path.join(app.config['UPLOAD_FOLDER'], filename)
            file.save(file_path)

            with open(file_path, 'rb') as f:
                raw_data = f.read()
            source_format = detect(raw_data)['encoding']
            print(source_format)

            with open(file_path, 'rU', encoding=source_format) as sf:
                content = sf.read()
                replaced_content = content.replace('Ý', 'İ').replace('ý', 'ı').replace('þ', 'ş').replace('ð',
                                                                                                         'ğ').replace(
                    'Þ', 'Ş')
                print(file_path)

                with open(file_path, 'w', encoding=target_format) as tf:
                    tf.write(replaced_content)

                return redirect('/')
    else:
        flash('Allowed file types are txt,srt')
        return redirect(request.url)
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