使用 swig 和 python 设置编译器标志

Question

我在将 boost 包含到我的 C++ 代码中时遇到问题，该代码是使用“swig”编译的。我想用 c++ 作为我的 python 东西的后端。

调用这两个命令

swig -c++ -python spherical_overlap.i
python setup.py build_ext --inplace

后者给了我以下错误

clang: warning: -lboost_system : 'linker' input unused
In file included from spherical_overlap_wrap.cxx:3427:
./spherical_overlap.h:8:10: fatal error: 'boost/math/special_functions/bessel.hpp' file not found
#include <boost/math/special_functions/bessel.hpp>

该文件位于那里。我想我必须为编译器设置以下标志

-I /usr/local/include

问题是，我不知道该怎么做。这是我的“setup.py”文件

#!/usr/bin/env python

from distutils.core import setup, Extension


spherical_overlap_module = Extension('_spherical_overlap',
                           sources=['spherical_overlap_wrap.cxx', 'spherical_overlap.cpp'],
                           swig_opts=['-c++', '-py3'],
                           extra_compile_args =['-lboost_system '],
                           )

setup (name = 'spherical_overlap',
       version = '0.1',
       author      = "SWIG Docs",
       description = """Simple swig spherical_overlap from docs""",
       ext_modules = [spherical_overlap_module],
       py_modules = ["spherical_overlap"],
       )

Answer 1

您可以执行以下任一操作：

1. 将

   include_dirs = ['/usr/local/include'],

   添加到

   Extension

   构造函数调用

2. 将以下内容添加到文件中

   setup.cfg

   ：

   [build_ext]
   include-dirs = /usr/local/include
   

3. 为

   include-dirs

   命令指定

   build_ext

   选项，即运行

   python setup.py build_ext --inplace --include-dirs /usr/local/include
   

4. 将

   -I/usr/local/include

   添加到

   CPPFLAGS

   环境变量，例如 run

   CPPFLAGS="-I/usr/local/include" python setup.py build_ext --inplace
   

第二种可能是首选方式，因为它反映了取决于本地系统配置的选项。