子查询有两个表

问题描述 投票:1回答:3

我有两张桌子:

__Table R_____

ID.....CustID....DATE
1......1.........2000-01-01
2......2.........2000-01-02
3......2.........2000-01-03
4......2.........2000-02-22
5......1.........2000-03-23

__Table Customers______

ID....NAME
1.....Lucas
2.....Michael

请问,如何从每个客户的NAME返回最后一个DATE的SELECT? (这条路):

Lucas......2000-03-23
Michael....2000-02-22
mysql sql select subquery recurrence
3个回答
0
投票

您可以使用:

select c.name,  max(r.date) 
from table_customers c
join table_r r on r.custid = c.id
group by c.id,  c.name;

0
投票

您需要的选择,使用MAX将返回最新日期:

SELECT customer.name, MAX(r.date)

来自两个表的join

FROM r INNER JOIN customer ON r.custid = customer.id

但是,如果您需要每个客户的最新日期,您需要group它:

GROUP BY r.custid;

0
投票
select c.name, r.date 
from table_customers c 
join table_r r on r.custid = c.id 
ORDER BY r.date DESC 
LIMIT 2 ;
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