如何捕获 FeignClient 异常

问题描述 投票:0回答:2

我尝试捕获从 FeignClient 连接的另一个微服务收到的异常。我制作了自定义 ErrorDecoder,并且

public class CustomErrorDecoder implements ErrorDecoder {

    private final Logger log = LoggerFactory.getLogger(getClass());

    private final ErrorDecoder defaultErrorDecoder = new Default();

    @Override
    public Exception decode(String methodKey, Response response) {

        if (response.status() >= 400 && response.status() <= 499) {
            log.info("----------------- "+methodKey+" , "+response.status()+" , "+ response.reason());
            return new RestApiException(99,99,"");
        }
        return defaultErrorDecoder.decode(methodKey, response);
    }
} 

RestApiException 扩展了 Exception。

@ControllerAdvice
public class GlobalControllerAdvice {

    private final Logger log = LoggerFactory.getLogger(getClass());

    @ExceptionHandler(RestApiException.class)
    public ResponseEntity<RestApiException> handleException(RestApiException exception, HttpServletRequest req) {
        log.error("Sending error to client ( "+req.getUserPrincipal().getName()+" ) \"{}\"", exception.getErrMsg());
        return new ResponseEntity<RestApiException>(exception, exception.getStatus());
    }

    @ExceptionHandler(Throwable.class)
    public ResponseEntity<RestApiException> handleException(Throwable throwable, HttpServletRequest req) {
        RestApiException exception=new RestApiException(HttpStatus.INTERNAL_SERVER_ERROR, 100, 100,
                throwable.getMessage());
        return handleException(exception, req);
    }

结果,当我得到<--- HTTP/1.1 400 Bad Request (5380ms) I've got default error messages

HttpStatus.INTERNAL_SERVER_ERROR, 100, 100, throwable.getMessage());

但不是预期的自定义异常,我尝试在 CustomErrorDecoder 中设置。

我做错了什么,为什么我不能调用 RetAppiException 并向其余客户端返回错误答案?

谢谢。

spring-mvc feign
2个回答
11
投票

无法用

@ControllerAdvice
捕获FeignClient的异常。异常处理程序不会捕获由 feign 客户端、错误解码器生成的异常..

一个简单的解决方案是捕获你的假调用,然后抛出你想要的异常。

try{
   feignClient.method();
} catch(Exception ex){
  //throw exceptions you want
  throw new YourException();
}

然后你就可以处理它了:

@ControllerAdvice
public class GlobalControllerAdvice {

    private final Logger log = LoggerFactory.getLogger(getClass());

    @ExceptionHandler(YourException.class)
    public ResponseEntity<RestApiException> handleException(RestApiException exception, HttpServletRequest req) {
        //impl
    }

}

0
投票

您可以通过捕获

HystrixRuntimeException
并将
getCause()
转换为
FeignClientException
来捕获假客户端异常。

示例:

@ExceptionHandler
public ResponseEntity<Problem> handleFeignException(HystrixRuntimeException ex, NativeWebRequest request) {
    final FeignException.FeignClientException feignClientException = (FeignException.FeignClientException) ex.getCause();
    return handleException(feignClientException, request);
}

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