PowerShell - 修剪下划线前后的文件名适用于小型文件集

问题描述 投票：0回答：1

这是我第一次尝试使用 PowerShell，但我有一个文件夹，其中包含数百个文件，如下所示。

  • 时间戳#1_文件名_of_the_Item_a650-d322205a2071.xls
  • 时间戳#1_File_Name_of_the_Item_a650-d3b580442072.txt
  • 时间戳#1_File_Name_of_the_Item_a650-d3bhnf5a2073.xlsx
  • 时间戳#1_File_Name_of_the_Item_a650-d3b523da2074.csv
  • 时间戳#2_File_Name_of_the_Item_a650-d3bbvx5a2075.xls
  • 项目文件名_a650-d3ddfe5a2075.pdf

我的最终目标是：

  1. 修剪之前的所有内容，包括第一个下划线

    a.除非它不以日期时间戳记开始

  2. 修剪后面的所有内容，包括最后一个下划线，但保留扩展名

  3. 将剩余的下划线替换为空格

  4. 找出为什么我无法将现有代码与以下文件一起使用

20231025041306_LLLLL_Aaaaaaaaaa_7777d4cb-6666631f-fa38-473e-a650-d3564505a2075.xls 20231025041406_LLLLL_Aaaaaaaaaa_8777befd-8 7765c3e-3164-4800-b102-a82d48aaaa52.xlsx 20231025041436_LLLLL_Aaaaaaaaaa_73d2bbbc.PDF 20231025041518_LLLLL_Aaaaaaaaaa_210zzz2c.csv 2023 1025041613_LLLLL_Aaaaaaaaaa_aqqqq1ad.txt 20231025041906_cccc_dddddd_rrrrrr_a6fff0d3.xls 20231025041935_cccc_dddddd_rrrrrr_f37ggg89.pdf 20231025042000_cc cc_dddddd_rrrrrr_9e812343.csv 20231025042026_cccc_dddddd_rrrrrr_d7522280.txt 20231025042229_LllllAaaaaaaa_OO_OoooTttt_37gggd7- 5e81ffhgedc77-4c8e-9fbc-d2996ggg0df1.xls 20231025042254_LllllAaaaaaaa_OO_OoooTttt_4fjjjfrgb-e3ec7993-92d7-4ab8-ad9e-83ejjjjj929b.xlsx 20 231025042329_LllllAaaaaaaa_OO_OoooTttt_c0fkkkkf2.pdf 20231025042410_LllllAaaaaaaa_OO_OoooTttt_b555tefd7f.csv 20231025042505_LllllAaaaaaaa_OO_ OoooTttt_9784g07e.txt 20231025042747_Ppppp_Rrrrr_Rrrrrr_2902e487-cc3c6chhhh074-4a2e-a97f-bfa0000a062e.xls 20231025042813_Ppppp_Rrrrr_Rrrrrr_aab8 4122-2fzzzz68-a706-49a5- a3ef-40030ffff0a3.xlsx 20231025042842_Ppppp_Rrrrr_Rrrrrrr_79cdgggd2.PDF 20231025042923_Ppppp_Rrrrr_Rrrrrrr_f07yyya8f.csv 20231025043220_Tttt_Ddddddd_R rrrrr_2444gr18d-13b4fb14-8fc2-45e0-b18b-59jkh6353d78.xlsx

出于某种原因，如果我对所有文件尝试我的代码，那么我会得到左侧的结果。但是，如果我删除任何一个文件，那么我会在右侧得到正确的结果。

一次全部 一个文件被删除
LLLLL啊啊啊啊啊.xls LLLLL啊啊啊啊啊.xls
LLLLL啊啊啊啊啊.xlsx LLLLL啊啊啊啊啊.xlsx
LLLLAaaaaaaa.pdf LLLLAaaaaaaa.pdf
LLLLL Aaaaaaaa.csv LLLLL Aaaaaaaa.csv
LLLLL啊啊啊啊啊.txt LLLLL啊啊啊啊啊.txt
dddddd.xls cccc dddddd rrrrrr.xls
dddddd.pdf cccc dddddd rrrrrr.pdf
dddddd.csv cccc dddddd rrrrrr.csv
dddddd.txt cccc dddddd rrrrrr.txt
OO.csv LllllAaaaaaaa OO OoooTttt.csv
OO.pdf LllllAaaaaaaa OO OoooTttt.pdf
OO.txt LllllAaaaaaaa OO OoooTttt.txt
OO.xls LllllAaaaaaaa OO OoooTttt.xls
OO.xlsx LllllAaaaaaaa OO OoooTttt.xlsx
Rrrrr.csv Ppppp 啦啦啦啦啦啦.csv
呜呜.pdf 噗噗噗噗.pdf
呜呜.xls 噗噗噗噗.xls
呜呜.xlsx 噗噗噗噗.xlsx
Tttt dddddd rrrrrr.xlsx Tttt_Ddddddd_Rrrrrrr.xlsx 
#My Code that I hobbled together from other posts
$path = “c:\\folder 1”

Get-ChildItem -Path $Path –File | ForEach-Object {
$items = $_.BaseName –split “_”
$newFileName = ($items\[1..($items.Length – 2)\] -join “_”) + $_.Extension
Rename-Item –Path $_.FullName -NewName $newFileName
}
Get-ChildItem -File $Path | Rename-Item –NewName {$_.name -replace “\_”, “ “}

到目前为止，我可以让大多数事情正常工作，但以下几点：

  1. 出于某种原因，对于下面的文件，代码似乎删除了比应有的字符更多的字符。如果删除任何一个文件，则所有文件都可以工作。
  2. 如果没有日期时间戳则不删除字符
  3. 如果文件重复，则跳过/重命名该文件
powershell special-characters file-rename character-trimming
1个回答
0
投票

这种方法可能对您有用，但尚不清楚时间戳的有效格式是什么。此示例中的正则表达式将时间戳视为以 14 个数字开头并后跟下划线的任何文件，此过滤还将排除任何不满足此匹配条件的文件，因此不会重命名。

使用相关文件名的演示：

$test = [System.IO.FileInfo[]] @(
    '20231025041306_LLLLL_Aaaaaaaaaa_7777d4cb-6666631f-fa38-473e-a650-d3564505a2075.xls'
    '20231025041406_LLLLL_Aaaaaaaaaa_8777befd-87765c3e-3164-4800-b102-a82d48aaaa52.xlsx'
    '20231025041436_LLLLL_Aaaaaaaaaa_73d2bbbc.PDF'
    '20231025041518_LLLLL_Aaaaaaaaaa_210zzz2c.csv'
    '20231025041613_LLLLL_Aaaaaaaaaa_aqqqq1ad.txt'
    '20231025041906_cccc_dddddd_rrrrrr_a6fff0d3.xls'
    '20231025041935_cccc_dddddd_rrrrrr_f37ggg89.pdf'
    '20231025042000_cccc_dddddd_rrrrrr_9e812343.csv'
    '20231025042026_cccc_dddddd_rrrrrr_d7522280.txt'
    '20231025042229_LllllAaaaaaaa_OO_OoooTttt_37gggd7-5e81ffhgedc77-4c8e-9fbc-d2996ggg0df1.xls'
    '20231025042254_LllllAaaaaaaa_OO_OoooTttt_4fjjjfrgb-e3ec7993-92d7-4ab8-ad9e-83ejjjjj929b.xlsx'
    '20231025042329_LllllAaaaaaaa_OO_OoooTttt_c0fkkkkf2.pdf'
    '20231025042410_LllllAaaaaaaa_OO_OoooTttt_b555tefd7f.csv'
    '20231025042505_LllllAaaaaaaa_OO_OoooTttt_9784g07e.txt'
    '20231025042747_Ppppp_Rrrrr_Rrrrrr_2902e487-cc3c6chhhh074-4a2e-a97f-bfa0000a062e.xls'
    '20231025042813_Ppppp_Rrrrr_Rrrrrr_aab84122-2fzzzz68-a706-49a5-a3ef-40030ffff0a3.xlsx'
    '20231025042842_Ppppp_Rrrrr_Rrrrrr_79cdgggd2.PDF'
    '20231025042923_Ppppp_Rrrrr_Rrrrrr_f07yyya8f.csv'
    '20231025043220_Tttt_Dddddd_Rrrrrr_2444gr18d-13b4fb14-8fc2-45e0-b18b-59jkh6353d78.xlsx'
)

$test |
    Where-Object BaseName -Match '(?<=^[0-9]{14}_).+(?=_)' |
    ForEach-Object { $Matches[0].Replace('_', ' ') + $_.Extension }

这将输出：

LLLLL Aaaaaaaaaa.xls
LLLLL Aaaaaaaaaa.xlsx
LLLLL Aaaaaaaaaa.PDF
LLLLL Aaaaaaaaaa.csv
LLLLL Aaaaaaaaaa.txt
cccc dddddd rrrrrr.xls
cccc dddddd rrrrrr.pdf
cccc dddddd rrrrrr.csv
cccc dddddd rrrrrr.txt
LllllAaaaaaaa OO OoooTttt.xls
LllllAaaaaaaa OO OoooTttt.xlsx
LllllAaaaaaaa OO OoooTttt.pdf
LllllAaaaaaaa OO OoooTttt.csv
LllllAaaaaaaa OO OoooTttt.txt
Ppppp Rrrrr Rrrrrr.xls
Ppppp Rrrrr Rrrrrr.xlsx
Ppppp Rrrrr Rrrrrr.PDF
Ppppp Rrrrr Rrrrrr.csv
Tttt Dddddd Rrrrrr.xlsx

如果这就是您正在寻找的内容，那么最终的代码将变为：

Get-ChildItem path\to\theFiles -File |
    Where-Object BaseName -Match '(?<=^[0-9]{14}_).+(?=_)' |
    Rename-Item -NewName { $Matches[0].Replace('_', ' ') + $_.Extension }

另请参阅 https://regex101.com/r/YMd0IS/1 了解正则表达式详细信息。

最新问题
© www.soinside.com 2019 - 2024. All rights reserved.