以编程方式将NSTableView绑定到NSArrayController

问题描述 投票:1回答:1

我正在尝试将NSTextView绑定到代码中的NSArrayController,并且已经关注了一些问题:hereherehere。我正在使用Xcode 9.2和Swift 4构建一个MacOS应用程序。

我有一个带有2个按钮的SegmentedControl:一个用于添加新对象,另一个用于删除。当我尝试将NSTextField绑定到添加到数组中的新创建的对象时,我崩溃了。

我的VeiwController代码:

private enum Columns {
  static let name = NSUserInterfaceItemIdentifier("NameColumn")
  static let age = NSUserInterfaceItemIdentifier("AgeColumn")
}

let arrayController: NSArrayController

let table: NSTableView

let buttons: NSSegmentedControl

// MARK: —Initialisation—

required init() {
  super.init(nibName: nil, bundle: nil)
  /// Code to create arrayController, table, and buttons 
  ///...

  /// Bindings.
  table.bind(.content,
             to: self.arrayController,
             withKeyPath: "arrangedObjects",
             options: nil)
  /// Delegates
  table.delegate = self
  buttons.target = self
  buttons.action = #selector(splitButtonClicked)
}

arrayController添加/删除对象的功能。 Person是一个简单的类,有2个属性(NameAge):

@objc func splitButtonClicked() {
  switch buttons.selectedSegment {
  case 0:
    let person = Person()
    person.name = "Alfred"
    person.age = 21
    arrayController.addObject(person)
   case 1:
    arrayController.removeObject(arrayController.selectedObjects)
  default:
    print("Switch case error")
  }
}

创建新表行的代码返回一个新的NSTextField,但是当我尝试绑定文本字段时我崩溃了,我不知道为什么:

func tableView(_ tableView: NSTableView, viewFor tableColumn: NSTableColumn?, row: Int) -> NSView? {
  guard let column = tableColumn else { return nil }
  let t = NSTextField(frame: NSRect(x: 0, y: 0, width: column.width, height: table.rowHeight))
  if column.identifier == Columns.name {
    /// Crashing on this line.
    t.bind(.value, to: t, withKeyPath: "objectValue.name", options: nil)
  } else if column.identifier == Columns.age {
    t.bind(.value, to: t, withKeyPath: "objectValue.age", options: nil)
  }
  return t
} 
swift macos cocoa cocoa-bindings
1个回答
1
投票

这2行:

let t = NSTextField(...)
t.bind(.value, to: t, withKeyPath: "objectValue.name", options: nil)

您将文本字段绑定到不存在的密钥路径上。如果展开表视图的视图层次结构,它将如下所示:

Table View > Column > Cell View > Text Field

您需要提供的是Cell View,文本字段嵌套在其中。

fileprivate extension NSUserInterfaceItemIdentifier {
    static let cellView = NSUserInterfaceItemIdentifier("CellView")
    static let name = NSUserInterfaceItemIdentifier("NameColumn")
    static let age = NSUserInterfaceItemIdentifier("AgeColumn")
}

extension ViewController: NSTableViewDelegate, NSTableViewDataSource {
    private func makeCell(frame: CGRect) -> NSTableCellView {
        // Reuse an existing cell if possible
        if let existingCell = table.makeView(withIdentifier: .cellView, owner: nil) as? NSTableCellView {
            return existingCell
        }

        // Make a new cell
        let textField = NSTextField(frame: frame)
        textField.drawsBackground = false
        textField.isBordered = false

        let cell = NSTableCellView(frame: frame)
        cell.identifier = .cellView
        cell.textField = textField
        cell.addSubview(textField)
        return cell
    }

    func tableView(_ tableView: NSTableView, viewFor tableColumn: NSTableColumn?, row: Int) -> NSView? {
        guard let column = tableColumn else { return nil }

        let cell = makeCell(frame: NSRect(x: 0, y: 0, width: column.width, height: table.rowHeight))

        // Varying the binding based on what column is being requested
        switch column.identifier {
        case .name:
            cell.textField?.bind(.value, to: cell, withKeyPath: "objectValue.name", options: nil)
        case .age:
            cell.textField?.bind(.value, to: cell, withKeyPath: "objectValue.age", options: nil)
        default:
            print("Unrecognized column '\(column.identifier)'")
        }
        return cell
    }
}
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