如何正确总结datetime(end_date和begin date之间的区别) - mysql

问题描述 投票:0回答:2

我在mysql中使用。我创建了表“Sikcness”,我添加了一条记录:

+--------+---------+---------+-------------+--------+----------+
| Id_SICK|ID_WORKER| BEGIN_DATE          | END_DATE            |
+--------+---------+---------+----------+------------+---------+
| 1      |   1     |2019-03-18 07:00:00  |2019-03-20 15:00:00  |  
+--------+---------+--------+------------+----------+----------+  

然后我想用命令总结时间(结束日期列和开始日期列之间的时间差):

SELECT SEC_TO_TIME(SUM(TIME_TO_SEC(Sickness.END_DATE) - TIME_TO_SEC(Sickness.BEGIN_DATE))) AS 'SICKNESS TIME' FROM Sickness WHERE ID_WORKER = 1

但我只有那个结果(这是不正确的):

SICKNESS TIME
08:00:00

该命令应该像这样计算:

+---------+-------------+--------+----------+
| BEGIN_DATE          | END_DATE            |
+---------+----------+------------+---------+
|2019-03-18 07:00:00  |2019-03-18 15:00:00  |  
+--------+------------+----------+----------+  
|2019-03-19 07:00:00  |2019-03-19 15:00:00  |  
+--------+------------+----------+----------+  
|2019-03-20 07:00:00  |2019-03-20 15:00:00  |  
+--------+------------+----------+----------+ 

那么这是正确的:

SICKNESS TIME
24:00:00

我应该写什么样的mysql查询?有任何想法吗?映入眼帘。

mysql datetime difference
2个回答
1
投票

您应该乘以天数差异的小时数差异:

mysql> SELECT SEC_TO_TIME(SUM((DATEDIFF(end_date, begin_date) + 1) * (TIME_TO_SEC(END_DATE) - TIME_TO_SEC(BEGIN_DATE)))) AS 'SICKNESS TIME' FROM Sickness WHERE ID_WORKER = 1;
+---------------+
| SICKNESS TIME |
+---------------+
| 24:00:00      |
+---------------+
1 row in set (0.00 sec)

使用TIME_FORMAT的另一个查询:

mysql> select time_format(SUM((datediff(end_date, begin_date) + 1) * (time(end_date) - time(begin_date))), '%H:%i:%s') as 'SICKNESS TIME' from Sickness where id_worker = 1;
+---------------+
| SICKNESS TIME |
+---------------+
| 24:00:00      |
+---------------+
1 row in set (0.00 sec)

您可以在SQL Fiddle上尝试此查询


0
投票

所以,你需要像这样计算它:

  1. 疾病第一天的小时数
  2. 疾病最后一天的小时数
  3. 疾病天数乘以8(即工作小时数)

完成后,您需要添加这些以获得结果,例如

SELECT
TIMESTAMPDIFF(HOUR, begin_date, CONCAT(DATE(begin_date), ' 15:00:00')) +
(TIMESTAMPDIFF(DAY, begin_date, end_date) - 1) * 8 +
TIMESTAMPDIFF(HOUR, CONCAT(DATE(end_date), ' 07:00:00'), end_date) AS time 
FROM test
WHERE worker = 1;

这是SQL Fiddle

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