project_site
模型具有一个属性submission_status
。我想从index#action那里设置相应状态的状态。我想在提交按钮上单击每一行以将相应的submission_status
更改为true
。如何在Rails 5中做到这一点?
index.html.erb
<table>
<thead>
<tr>
<th>Uploaded Date</th>
<th>Attendance File</th>
<th>Submit Attendance</th>
</tr>
</thead>
<tbody>
<% @project_sites.each do |project_site| %>
<tr>
<td><%= project_site.created_at.strftime('%d-%m-%Y') %></td>
<td><%= link_to "View Attendance", project_site.attendance.url, :class => "fi-page-export-csv" %></td>
<td>
<%= form_for ProjectSite.new do |f| %>
<%#f.hidden_field :project_site_id, value: project_site.id%>
<%=f.hidden_field :submission_status, value: true%>
<div>
<%= f.submit 'Submit', :class => 'button primary small float-right' %>
</div>
<% end %>
</tr>
<% end %>
</tbody>
</table>
You have to pass the id of project_site for which you want to update the submission_status and on the controller updates the same project_site(id pass as hidden field), for this you need write **ajax** call
<table>
<thead>
<tr>
<th>Uploaded Date</th>
<th>Attendance File</th>
<th>Submit Attendance</th>
</tr>
</thead>
<tbody>
<% @project_sites.each do |project_site| %>
<tr>
<td><%= project_site.created_at.strftime('%d-%m-%Y') %></td>
<td><%= link_to "View Attendance", project_site.attendance.url, :class => "fi-page-export-csv" %></td>
<td>
<%= form_for ProjectSite.new do |f| %>
<%#f.hidden_field :project_site_id, value: project_site.id%>
<%=f.hidden_field :submission_status, value: true%>
<%= f.hidden_field :project_site_id, project_site.id%>
<div>
<%= f.submit 'Submit', :class => 'button primary small float-right' %>
</div>
<% end %>
</tr>
<% end %>
</tbody>
</table>