如何根据 JavaScript 中的日期返回当月总计(React)

问题描述 投票:0回答:1

我写了一个钩子来根据月份计算销售额来设置图表数据。

工作很好,但我不满意。

是否有不同或简单的方法来避免重复并使代码干净且可扩展!

注意:我不与公司或团队合作 - (自学)

我想计算当月每天的总数并返回新的对象数组

功能:



const month = (date) => new Date(date).toLocaleString('default', { month: 'long' });

export const useGetChartData = (orders) => {

  const orderTotal = orders.length
  const orderTotalsArray = orders.map(order => (+order.total) + (+order.total_tax));
  const sumOrders = orderTotalsArray?.reduce((inc, a) => inc + a, 0);
  const getMonthFromDateAndTotals = orders?.map(order => (
    {
      date: (order.date_paid ? month(order.date_paid) : month(order.date_modified)),
      total: +order.total + +order.total_tax
    }));

  const sendToChart = getMonthFromDateAndTotals.filter(o => o.total > 0);
  //filter!
  const January = sendToChart.filter((d) => d.date == 'January')
  const February = sendToChart.filter((d) => d.date == 'February')
  const March = sendToChart.filter((d) => d.date == 'March')
  const April = sendToChart.filter((d) => d.date == 'April')
  const May = sendToChart.filter((d) => d.date == 'May')
  const June = sendToChart.filter((d) => d.date == 'June')
  const July = sendToChart.filter((d) => d.date == 'July')
  const August = sendToChart.filter((d) => d.date == 'August')
  const September = sendToChart.filter((d) => d.date == 'September')
  const October = sendToChart.filter((d) => d.date == 'October')
  const November = sendToChart.filter((d) => d.date == 'November')
  const December = sendToChart.filter((d) => d.date == 'December')
  // 
  const totalsPerMonths = [
    //reduce! 
    { month: 'January', total: January?.reduce((inc, a) => inc + a.total, 0) },
    { month: 'February', total: February?.reduce((inc, a) => inc + a.total, 0) },
    { month: 'March', total: March?.reduce((inc, a) => inc + a.total, 0) },
    { month: 'April', total: April?.reduce((inc, a) => inc + a.total, 0) },
    { month: 'May', total: May?.reduce((inc, a) => inc + a.total, 0) },
    { month: 'June', total: June?.reduce((inc, a) => inc + a.total, 0) },
    { month: 'July', total: July?.reduce((inc, a) => inc + a.total, 0) },
    { month: 'August', total: August?.reduce((inc, a) => inc + a.total, 0) },
    { month: 'September', total: September?.reduce((inc, a) => inc + a.total, 0) },
    { month: 'October', total: October?.reduce((inc, a) => inc + a.total, 0) },
    { month: 'November', total: November?.reduce((inc, a) => inc + a.total, 0) },
    { month: 'December', total: December?.reduce((inc, a) => inc + a.total, 0) },
    // 
  ];

  const dataVisualizationToChart = totalsPerMonths.filter(vd => vd.total > 0);
  return {
    dataVisualizationToChart,
    orderTotal,
    sumOrders
  };
};

用途:

  const { data: orders, isLoading: ordersLoading, errors: orderErrors} = useGetShopData("orders");
  const { dataVisualizationToChart, sumOrders } = useGetChartData(orders)

返回:

{
  "dataVisualizationToChart": [
    {"month": "February","total": 1875.96},
    { "month": "March", "total": 1362.46},
    { "month": "April","total": 66.05000000000004},
  ],
  "orderTotal": 70,
  "sumOrders": 13064
}```



javascript reactjs filter map-function
1个回答
0
投票

我会建议这样的事情:

创建monthNames对象:将月份的数值映射到字符串名称。

const monthNames = {
'01': 'January',
'02': 'February',
'03': 'March',
'04': 'April',
'05': 'May',
'06': 'June',
'07': 'July',
'08': 'August',
'09': 'September',
'10': 'October',
'11': 'November',
'12': 'December'
};

我没有为每个月创建单独的数组,然后计算总数,而是使用reduce 在一次传递中按月对总数进行分组。

totalsPerMonths 的结果将是一个对象,其中键是唯一日期(月份),值是每个月的总和。

const totalsPerMonths = sendToChart.reduce((acc, current) => {
    if (!acc[current.date]) {
        acc[current.date] = 0;
    }
    acc[current.date] += current.total;
    return acc;
}, {});

在这里,我使用 MonthNames 映射将月份的数值提取到字符串名称中。

减少后,我通过迭代分组和减少对象的键来构造 dataVisualizationToChart。

const dataVisualizationToChart = Object.keys(totalsPerMonths).map(dateStr => {
    const [year, month] = dateStr.split('-');
    return {
        month: monthNames[month],
        total: totalsPerMonths[dateStr]
    };
});

希望我的解决方案对您有帮助!

我建议你在 LeetCode 上解决与数组和结果聚合相关的问题。它确实有助于解决未来类似的任务!

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