我有这个函数,我想画一个自循环。我怎样才能做到这一点?
边存在,但我认为这只是这个例子中的一个点是 (1,1) 并且我无法添加节点的名称。
我的目标是从邻接矩阵绘制一个图。有没有更好的方法来做到这一点?
import networkx as nx
import matplotlib.pyplot as plt
from matplotlib.patches import FancyArrowPatch, Circle
import numpy as np
def draw_network(G, pos, ax, sg=None):
for n in G:
c = Circle(pos[n], radius=0.05, alpha=0.7)
ax.add_patch(c)
G.nodes[n]['patch'] = c
x, y = pos[n]
seen = {}
for (u, v, d) in G.edges(data=True):
n1 = G.nodes[u]['patch']
n2 = G.nodes[v]['patch']
rad = 0.1
if (u, v) in seen:
rad = seen.get((u, v))
rad = (rad + np.sign(rad) * 0.1) * -1
alpha = 0.5
color = 'k'
e = FancyArrowPatch(n1.center, n2.center, patchA=n1, patchB=n2,
arrowstyle='-|>',
connectionstyle='arc3,rad=%s' % rad,
mutation_scale=10.0,
lw=2,
alpha=alpha,
color=color)
seen[(u, v)] = rad
ax.add_patch(e)
return e
G = nx.MultiDiGraph([(1, 2), (1, 1), (1, 2), (2, 3), (3, 4), (2, 4),
(1, 2), (1, 2), (1, 2), (2, 3), (3, 4), (2, 4)]
)
pos = nx.spring_layout(G)
ax = plt.gca()
draw_network(G, pos, ax)
ax.autoscale()
plt.axis('equal')
plt.axis('off')
plt.show()
看来你的方法使用 matplotlib 是相当先进的,但我仍然建议使用专门的图形绘制库(就像 networkx 文档那样)。 随着图变大,会出现更多问题 - 但这些问题已经在这些库中得到解决。
“首选”选项是graphviz,它可以很好地处理绘制多图。 您可以从 networkx 图形编写点文件,然后使用图形绘制工具之一(例如 dot、neato 等)。
import networkx as nx
from networkx.drawing.nx_agraph import to_agraph
# define the graph as per your question
G=nx.MultiDiGraph([(1,2),(1,1),(1,2),(2,3),(3,4),(2,4),
(1,2),(1,2),(1,2),(2,3),(3,4),(2,4)])
# add graphviz layout options (see https://stackoverflow.com/a/39662097)
G.graph['edge'] = {'arrowsize': '0.6', 'splines': 'curved'}
G.graph['graph'] = {'scale': '3'}
# adding attributes to edges in multigraphs is more complicated but see
# https://stackoverflow.com/a/26694158
G[1][1][0]['color']='red'
A = to_agraph(G)
A.layout('dot')
A.draw('multi.png')
请注意,您还可以轻松地从 ipython shell 中调用绘图: https://stackoverflow.com/a/14945560