使用python

Question

def create_message_with_thread_id(sender, to, subject, message_text, thread_id):
    from email.message import EmailMessage
    message = EmailMessage()

    message.set_content(message_text)

    message['To'] = to
    message['From'] = sender
    message['Subject'] = subject
    message['In-Reply-To'] = thread_id
    message['References'] = thread_id

    # encoded message
    encoded_message = base64.urlsafe_b64encode(message.as_bytes()) \
        .decode()

    message = {
        'raw': encoded_message,
        }

    return message
    

# Function to send the message

def send_message(service, user_id, message):
    try:
        message = service.users().messages().send(
            userId=user_id, body=message).execute()
        print("Message Id: %s" % message['id'])
        return message
    except HttpError as e:
        print("An error occurred: %s" % e)
        return None

对于

In-Reply-To

和

Answer 1

标题，您需要消息ID，您可以从要回复的消息的标题中检索：

Message-Id

需要在您发送到Gmail API的响应中使用线程ID，与原始消息相同的级别：

    message_id = previous_message['Message-Id']

    …
    message['In-Reply-To'] = message_id
    message['References'] = message_id