我正在尝试编写 Laravel 数据库迁移,但收到以下关于外键的错误:
[Illuminate\Database\QueryException]
SQLSTATE[42000]: Syntax error or access violation: 1072 Key column 'category_id' doesn't exist in table (SQL: alter table `subcategories` add constraint subcategories_category_id_foreign foreign key (`category_id`) references `categories` (`id`))
[PDOException]
SQLSTATE[42000]: Syntax error or access violation: 1072 Key column 'category_id' doesn't exist in table
categories
和 subcategories
表确实已创建,但外键并未创建。这是我的迁移:
<?php
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Database\Migrations\Migration;
class CreateCategoryTable extends Migration
{
/**
* Run the migrations.
*
* @return void
*/
public function up()
{
Schema::create('categories', function ($table) {
$table->increments('id')->unsigned();
$table->string('name')->unique();
});
Schema::create('subcategories', function ($table) {
$table->increments('id')->unsigned();
$table->foreign('category_id')->references('id')->on('categories');
$table->string('name')->unique();
});
}
/**
* Reverse the migrations.
*
* @return void
*/
public function down()
{
Schema::drop('categories');
Schema::drop('subcategories');
}
}
有什么想法吗?谢谢!
您应该在创建外键之前创建列:
$table->integer('category_id')->unsigned();
$table->foreign('category_id')->references('id')->on('categories');
文档:http://laravel.com/docs/5.1/migrations#foreign-key-constraints
正如Limon Monte提到的,首先创建列,然后添加外键约束
$table->foreignId('category_id');
$table->foreign('category_id')->references('id')->on('categories');
整数对我不起作用。相反,我使用 bigInteger 来创建外键:
$table->bigInteger('category_id')->unsigned()->index()->nullable();
$table->foreign('category_id')->references('id')->on('categories')->onDelete('cascade');
我忘记将
->get()
添加到我调用的方法中。
只需使用
$table->foreignId('category_id')->references('id')->on('categories');