在下面的页面摘录中，我需要能够单击“应用程序配置文件” 但无论我尝试什么，我都无法让它发挥作用。 我不断收到 OpenQA.Selenium.NoSuchElementException。
<body>
<div id="main-page">
<div class="page">
</div>
<div id="page-header" class="page-header">
<div id="page-header-navbar" class="page-header-navbar">
<div class="page-header-contents">
<div class="page-header-navbar-left">
<div class="nav-menus">
<div class="nav-menu" data-item="dashboard">
<div class="nav-menu-header selected -js-header">
<i class="nav-menu-icon fa fa-tachometer"></i> <span
class="nav-menu-header-label">Dashboard</span>
</div>
</div>
<div class="nav-menu" data-item="policy">
<div class="nav-menu-header -js-header">
<i class="nav-menu-icon fa fa-sitemap"></i><span
class="nav-menu-header-label">App Profiles</span>
</div>
</div>
</div>
</div>
</div>
</div>
</div>
</div>
</body>
这些已经尝试过：
IWebElement element = driver.FindElement(By.XPath("//div[@class='nav-menu-header-label' and text()='App Profiles']"));
IWebElement appProfilesElement = driver.FindElement(By.XPath("//span[text()='应用程序配置文件']"));
先尝试等待：
from selenium.webdriver.support.ui import WebDriverWait
# wait for 10 seconds
wait = WebDriverWait(driver, 10)
xpath = "//div[@class='nav-menu-header-label' and text()='App Profiles']"
element = wait.until(EC.element_to_be_clickable((By.XPATH, xpath)))
element.click()