我试图解组一个类型接口的数据。所以我需要将接口类型转换为[] byte并将其传递给unmarshall。我试过了
err := json.Unmarshal([]byte(kpi), &a)
=>失败了kpidata, res := kpi.([]byte)
=>将接口转换为字节,kpidata为零那么我们有什么方法可以转换它吗?
在你的sample代码中,data
应该是JSON编码的(用简单的单词String),所以你使用Unmarshal
的方式是错误的:
// Unmarshal parses the JSON-encoded data and stores the result // in the value pointed to by v. If v is nil or not a pointer, // Unmarshal returns an InvalidUnmarshalError. func Unmarshal(data []byte, v interface{}) error
在The Go Playground和this: []string{"art", "football"}
上尝试:
package main
import (
"encoding/json"
"fmt"
)
func main() {
// ********************* Marshal *********************
u := map[string]interface{}{}
u["name"] = "kish"
u["age"] = 28
u["work"] = "engine"
//u["hobbies"] = []string{"art", "football"}
u["hobbies"] = "art"
b, err := json.Marshal(u)
if err != nil {
panic(err)
}
fmt.Println(string(b))
// ********************* Unmarshal *********************
var a interface{}
err = json.Unmarshal(b, &a)
if err != nil {
fmt.Println("error:", err)
}
fmt.Println(a)
}
输出:
{"age":28,"hobbies":"art","name":"kish","work":"engine"}
map[name:kish work:engine age:28 hobbies:art]
你想要解组它,所以试试this简单的工作示例([]byte(kpi.(string)
):
package main
import (
"encoding/json"
"fmt"
)
func main() {
var kpi interface{} = st
var a []Animal
err := json.Unmarshal([]byte(kpi.(string)), &a)
if err != nil {
fmt.Println("error:", err)
}
fmt.Println(a)
}
type Animal struct {
Name string
Order string
}
var st = `[
{"Name": "Platypus", "Order": "Monotremata"},
{"Name": "Quoll", "Order": "Dasyuromorphia"}
]`
输出:
[{Platypus Monotremata} {Quoll Dasyuromorphia}]
使用(example)工作[]byte(*kpi.(*string))
:
package main
import (
"encoding/json"
"fmt"
)
func main() {
var kpi interface{} = &st
var a []Animal
err := json.Unmarshal([]byte(*kpi.(*string)), &a)
if err != nil {
fmt.Println("error:", err)
}
fmt.Println(a)
}
type Animal struct {
Name string
Order string
}
var st = `[
{"Name": "Platypus", "Order": "Monotremata"},
{"Name": "Quoll", "Order": "Dasyuromorphia"}
]`
package main
import (
"encoding/json"
"fmt"
)
func main() {
u := map[string]interface{}{}
u["1"] = "one"
b, err := json.Marshal(u)
if err != nil {
panic(err)
}
fmt.Println(string(b))
}
输出:
{"1":"one"}
我希望这有帮助。