将 JSON 常量序列化为 C# 中的枚举

Question

我正在编写一个 C# 程序，以“此 JSON 模式”的形式导入 JSON 数据。该模式的作者选择将一些枚举类型实现为具有 const 字符串属性的对象数组，如下所示： anyOf

和

  "ApplicationType": {
  "$id": "#ApplicationType",
  "anyOf": [
    {
      "additionalProperties": false,
      "properties": {
        "description": {
          "const": "Consent to make small (minor material) changes to a project with Planning Permission",
          "type": "string"
        },
        "value": {
          "const": "amendment.minorMaterial",
          "type": "string"
        }
      },
      "required": [
        "value",
        "description"
      ],
      "type": "object"
    },
    {
      "additionalProperties": false,
      "properties": {
        "description": {
          "const": "Consent to make small (non-material) changes to a project with Planning Permission",
          "type": "string"
        },
        "value": {
          "const": "amendment.nonMaterial",
          "type": "string"
        }
      },
      "required": [
        "value",
        "description"
      ],
      "type": "object"
    },

NJsonSchema 将它们导入为具有可写字符串属性的对象，并且不导入 const 值。我想导入这些常量值，以便我可以验证和导入数据。我提出了三种解决方案，但我对其中任何一个都不是特别满意。

作为枚举导入我可以将以上内容导入为以下带注释的枚举：

  "FileType": {
  "$id": "#FileType",
  "anyOf": [
    {
      "additionalProperties": false,
      "properties": {
        "description": {
          "const": "Elevations - existing",
          "type": "string"
        },
        "value": {
          "const": "elevations.existing",
          "type": "string"
        }
      },
      "required": [
        "value",
        "description"
      ],
      "type": "object"
    },
    {
      "additionalProperties": false,
      "properties": {
        "description": {
          "const": "Elevations - proposed",
          "type": "string"
        },
        "value": {
          "const": "elevations.proposed",
          "type": "string"
        }
      },
      "required": [
        "value",
        "description"
      ],
      "type": "object"
    },

和

enum EApplicationType
{
    [Code("amendment.minorMaterial")]
    ConsentToMakeSmallMinorMaterialChangesToAProjectWithPlanningPermission,
    [Code("amendment.nonMaterial")]
    ConsentToMakeSmallNonMaterialChangesToAProjectWithPlanningPermission,

这样做的好处是每个列表都有自己的类型，但缺点是任何转换都必须使用反射，并且迭代所有值需要大量反射。我可以通过加载字典一次来解决这个问题。

使用类和字符串属性我可以将值作为字符串导入到类中：

enum EFileType
{
    [Code("elevations.existing")]
    ElevationsExisting,
    [Code("elevations.proposed")]
    ElevationsProposed,

和

static class ApplicationType
{
    public static string ConsentToMakeSmallMinorMaterialChangesToAProjectWithPlanningPermission => "amendment.minorMaterial";
    public static string ConsentToMakeSmallNonMaterialChangesToAProjectWithPlanningPermission => "amendment.nonMaterial";

这里的优点是简单，我们将简单地比较字符串，但这最终不会被输入，我们将传递字符串而不是父类型。枚举所有值也需要再次反射。

使用类/对象另一种选择是像 JSON 模式一样使用整个对象，如下所示：

static class FileType
{
    public static string ElevationsExisting => "elevations.existing";
    public static string ElevationsProposed => "elevations.proposed";

或

public class ConsentToDisplayAnAdvertisement : IApplicationType
{
    public string Description => "ConsentToDisplayAnAdvertisement";
    public string Value => "advertConsent";

    public int CompareTo(object obj)
    {
        return Value.CompareTo((obj as IApplicationType).Value);
    }

}

虽然这大部分有效，但使用带有对象的

public static class EEApplicationType
{
    public static DescriptionValue ConsentToMakeSmallChangesToAProjectWithPlanningPermission = new DescriptionValue
    (
        "ConsentToMakeSmallChangesToAProjectWithPlanningPermission",
        "amendment"
    );

语句并不直接，并且再次需要反射来迭代所有值。还有我错过的更好的方法吗？

Corvus.JsonSchema 支持 const 值，并为您提供 Match() 函数来切换它们。

Answer 1