我有这个数组:
Array (
[0] => Array (
[TaxeName] => TPS
[TaxeAmount] => 7
[Price] => 14
)
[1] => Array (
[TaxeName] => TVQ
[TaxeAmount] => 9.975
[Price] => 10
)
[2] => Array (
[TaxeName] => TVQ
[TaxeAmount] => 9.975
[Price] => 18
)
)
我如何获得另一个数组:
- 将
TaxeName
和 TaxeAmount
和 Price
?
像这样:
Array (
[0] => Array (
[TaxeName] => TPS
[TaxeAmount] => 7
[Price] => 14
)
[1] => Array (
[TaxeName] => TVQ
[TaxeAmount] => 9.975
[Price] => 28
)
)
可以通过嵌套来完成
foreach
:
$original = array(.......); // your current array
$newArr = array();
foreach($original as $origVal){
$exists = false;
foreach($newArr as $key => $newVal){
if($newVal['TaxeName'] == $origVal['TaxeName']){
$newArr[$key]['Price'] += $origVal['Price'];
$exists = true;
break;
}
}
if(!$exists){
$newArr[] = $origVal;
}
}
输出
Array
(
[0] => Array
(
[TaxeName] => TPS
[TaxeAmount] => 7
[Price] => 14
)
[1] => Array
(
[TaxeName] => TVQ
[TaxeAmount] => 9.975
[Price] => 28
)
)
也许是这样的:
$final = array();
foreach ($arr as $subarr)
{
if (!isset($final[$subarr['TaxeName']]))
{
$final[$subarr['TaxeName']] = array('Price' => 0);
}
$final[$subarr['TaxeName']]['TaxeName'] = $subarr['TaxeAmount'];
$final[$subarr['TaxeName']]['TaxeName'] = $subarr['TaxeName'];
$final[$subarr['TaxeName']]['Price'] = $final[$subarr['TaxeName']]['Price'] + $subarr['Price'];
}
这个想法是用您需要的值创建一个新数组,并将价格设置为 0 进行初始化,以便您可以在 foreach 中递增它
你也可以这样做:
<?php
// Source
$myData = array(
array(
'TaxeName' => 'TPS',
'TaxeAmount' => 7,
'Price' => 14,
),
array(
'TaxeName' => 'TVQ',
'TaxeAmount' => 9.975,
'Price' => 10,
),
array(
'TaxeName' => 'TVQ',
'TaxeAmount' => 9.975,
'Price' => 18,
)
);
// Helper Function
function parseData($data)
{
$parsedData = array();
if (is_array($data)) {
foreach ($data as $dataItem) {
if (!array_key_exists($dataItem['TaxeName'], $parsedData)) {
$parsedData[$dataItem['TaxeName']] = array(
'TaxeName' => $dataItem['TaxeName'],
'TaxeAmount' => $dataItem['TaxeAmount'],
'Price' => floatval($dataItem['Price'])
);
} else {
$parsedData[$dataItem['TaxeName']]['Price'] += floatval($dataItem['Price']);
}
}
}
return array_values($parsedData);
}
// Test
$parsed_data = parseData($myData);
var_dump($parsed_data);
?>
输出:
只要使用这个函数,输入是你的数组,输出是你需要的数组:
function calculate(array $input){
$output = [];
foreach ($input as $v){
if (array_key_exists($v['TaxeName'], $output)){
$output[$v['TaxeName']]['Price'] += $v['Price'];
} else {
$output[$v['TaxeName']] = $v;
}
}
return array_values($output);
}
我知道这里不欢迎具有外部类的解决方案。我展示这个只是为了说明“对 TaxeName 和 TaxeAmount 进行分组”任务。
//use class tablearray from https://github.com/jspit-de/tableArray
$data = [
['TaxeName' => 'TPS', 'TaxeAmount' => 7, 'Price' => 14],
['TaxeName' => 'TVQ', 'TaxeAmount' => 9.975, 'Price' => 10],
['TaxeName' => 'TVQ', 'TaxeAmount' => 9.975, 'Price' => 18],
['TaxeName' => 'TVQ', 'TaxeAmount' => 19.975, 'Price' => 23]
];
$newData = tableArray::create($data)
->filterGroupSum('Price',['TaxeName','TaxeAmount'])
->fetchAll()
;
echo '<pre>';
var_export($newData);
输出:
array (
0 =>
array (
'TaxeName' => 'TPS',
'TaxeAmount' => 7,
'Price' => 14,
),
1 =>
array (
'TaxeName' => 'TVQ',
'TaxeAmount' => 9.975,
'Price' => 28,
),
2 =>
array (
'TaxeName' => 'TVQ',
'TaxeAmount' => 19.975,
'Price' => 23,
),
)
foreach()
或
array_reduce()
为了避免在结果数组中创建和(稍后删除)临时分组键,请创建一个代表每个唯一组的引用变量,并将该引用推入结果数组中。 当遇到组的后续成员时,仅对引用进行修改。
$result = [];
foreach ($array as $row) {
// create group if needed
if (!isset($ref[$row['TaxeName']])) {
$ref[$row['TaxeName']] = $row; // assign base elements of group
$result[] =& $ref[$row['TaxeName']];
continue;
}
// manipulate data within group
$ref[$row['TaxeName']]['Price'] += $row['Price'];
}
var_export($result);
输出:
array (
0 =>
array (
'TaxeName' => 'TPS',
'TaxeAmount' => 7,
'Price' => 14,
),
1 =>
array (
'TaxeName' => 'TVQ',
'TaxeAmount' => 9.975,
'Price' => 28,
),
)
如果要按多列进行分组(例如 TaxeName
和
TaxeAmount
),则在迭代每行时形成多个列值的复合字符串。换句话说,将上述脚本中所有位置的
$row['TaxeName']
替换为
"{$row['TaxeName']} {$row['TaxeAmount']}"
。