通过共享列对两个二维数组的行进行分组，并在没有可用数据的情况下添加默认值[重复]

Question

我有两个二维数组，例如

Array
(
[0] => Array
    (
        [0] => 2022-01-19
        [1] => 6
    )
[1] => Array
    (
        [0] => 2022-01-20
        [1] => 1
    )
[2] => Array
    (
        [0] => 2022-01-21
        [1] => 1
    )
[3] => Array
    (
        [0] => 2022-01-22
        [1] => 2
    )
)

和

Array
(
[0] => Array
    (
        [0] => 2022-01-17
        [1] => 6
    )
[1] => Array
    (
        [0] => 2022-01-18
        [1] => 1
    )
[2] => Array
    (
        [0] => 2022-01-21
        [1] => 1
    )
[3] => Array
    (
        [0] => 2022-01-23
        [1] => 2
    )
)

我需要将它们合并到相关的日期值上，并且我想要以下结果：

Array
(
[0] => Array
    (
        [0] => 2022-01-17
        [1] => 0
        [2] => 6
    )
[1] => Array
    (
        [0] => 2022-01-18
        [1] => 0
        [2] => 1
    )
[2] => Array
    (
        [0] => 2022-01-19
        [1] => 6
        [2] => 0
    )
[3] => Array
    (
        [0] => 2022-01-20
        [1] => 1
        [2] => 0
    )
[4] => Array
    (
        [0] => 2022-01-21
        [1] => 1
        [2] => 1
    )
[5] => Array
    (
        [0] => 2022-01-22
        [1] => 2
        [2] => 0
    )
[6] => Array
    (
        [0] => 2022-01-23
        [1] => 0
        [2] => 2
    )
)

我尝试使用以下代码，但没有成功。

$final_array = [];
foreach ($openTicket as $val) {
    $closeTicketNo = 0;
    foreach ($closeTicket as $value) {
        if ($val[0] == $value[0]) {
            $closeTicketNo = $value[1];
        }
    }
    $final_array[] = [$val[0], $val[1], $closeTicketNo];
}

我从 $openTicket 获取所有元素，但没有从 $closeTicket 获取所有元素到我的结果数组 $final_array

Answer 1

此代码首先从每个数组中的第一个值中查找所有唯一日期（使用

array_unique

）（

array_column

获取值，然后

array_merge

将它们放入 1 个数组中）。

然后它按日期索引每个数组（再次使用

array_column

）。

最后循环遍历唯一的日期，并使用值将新元素添加到输出中（使用

?? 0

，这样如果不存在值，数组仍会正确填充）...

$dates = array_unique(array_merge(array_column($openTicket, 0), array_column($closedTicket, 0)));
$open = array_column($openTicket, 1, 0);
$closed = array_column($closedTicket, 1, 0);
$finalArray = [];
foreach ($dates as $date) {
    $finalArray[] = [$date, $open[$date] ?? 0, $closed[$date] ?? 0];
}

Answer 2

你可以尝试像这个

$array1 = [
    ['2022-01-19',6],
    ['2022-01-20',1],
    ['2022-01-21',0]
];

$array2 = [
    ['2022-01-17',6],
    ['2022-01-20',2],
    ['2022-01-21',1]
];


function mergeMultiple($array1,$array2){
    foreach($array1 as $item1){
        $mergedArray[$item1[0]] = $item1;
    }

    foreach($array2 as $item2){
        if(isset($mergedArray[$item2[0]])){
             array_push($mergedArray[$item2[0]],$item2[1]);
             $mergedArray[$item2[0]] = $mergedArray[$item2[0]];
        }else{
          $mergedArray[$item2[0]] = $item2;
        }
    }

    return array_values($mergedArray);
}

$mergedArray = mergeMultiple($array1,$array2);
ksort($mergedArray);
print_r($mergedArray);