Laravel今天和明天都会得到用户的生日

Question

我有这个查询来获得明天和今天的生日用户：

$birthday[Carbon::now()->format('Y-m-d')] = User::whereRaw("DATE_FORMAT(birthday, '%m-%d') = DATE_FORMAT(now(),'%m-%d')")
        ->orWhereRaw("DATE_FORMAT(birthday,'%m-%d') = '02-29' and DATE_FORMAT(birthday, '%m') = '02' AND 
        LAST_DAY(NOW()) = DATE(NOW())")
        ->selectRaw('first_name, last_name, email, birthday')
        ->get();

$birthday[Carbon::now()->addDay()->format('Y-m-d')] = User::whereRaw("DATE_FORMAT(birthday, '%m-%d') = DATE_FORMAT(NOW() + INTERVAL 1 DAY, '%m-%d')")
        ->orWhereRaw("DATE_FORMAT(birthday,'%m-%d') = '02-29' and DATE_FORMAT(birthday, '%m') = '02' AND 
            LAST_DAY(NOW()) = DATE(NOW())")
        ->selectRaw('first_name, last_name, email, birthday')
        ->get();

 return $birthday;

该查询将给我这个结果：

{
    "2016-03-30": [
        {
          "first_name": "Harmon",
          "last_name": "Olson",
          "email": "[email protected]",
          "birthday": "1990-03-30"
        },
        {
          "first_name": "John",
          "last_name": "Doe",
          "email": "[email protected]",
          "birthday": "1990-03-30"
        },
    ],
    "2016-03-31": [
        {
          "first_name": "User10",
          "last_name": null,
          "email": "[email protected]",
          "birthday": "1990-03-31"
        }
    ]
}

当然它工作正常，结果正是我想要的，但我认为我的查询可以缩短（结合查询成为一个）来获得我想要的东西。

有什么建议如何缩短它？

提前致谢！

Answer 1

您可以避免RAW查询：

$birtday['today'] = User::whereDate('birthday', '=', Carbon::today()->toDateString());

$birtday['tomorrow'] = User::whereDate('birthday', '=', Carbon::tomorrow()->toDateString());

Answer 2

试试这个：

\App\User::whereRaw("STR_TO_DATE( CONCAT(YEAR(CURDATE()), '-', MONTH(dob), '-', DAY(dob), '%Y-%m-%d' ) = DATE_ADD(CURDATE(), INTERVAL 0 DAY)")->get();

或明天：

\App\User::whereRaw("STR_TO_DATE( CONCAT(YEAR(CURDATE()), '-', MONTH(dob), '-', DAY(dob), '%Y-%m-%d' ) = DATE_ADD(CURDATE(), INTERVAL 1 DAY)")->get();