虽然每次循环重复两次，并且CPU仅在为剪刀选择'S'时才得分。另一个问题是，如何使它变得更高级以及在哪里添加该功能？我必须使用字符“ r”，“ s”和“ p”，而不是1,2,3来接受用户输入。不确定如何解决此问题
#include <stdlib.h>
#include<time.h>
int main () {
char player1;
int player2;
int userScore = 0, cpuScore = 0;
player2 = rand ( ) % 3 + 1;
srand ((int) time (NULL));
int count = 0;
while(count <= 10) {
printf("\nEnter p for Paper, r for rock, or S for scissor: ");
scanf("%c", &player1);
switch(player1) {
case 'P' :
if(player1 == 'P' && player2 == 1) {
printf("Draw!");
break;
} else if(player1 == 'P' && player2 == 2) {
userScore++;
printf("User won this one!");
break;
} else {
cpuScore++;
printf("CPU won this one!");
break;
}
case 'R':
if(player1 == 'R' && player2 == 2) {
printf("Draw!");
break;
} else if(player1 == 'R' && player2 == 3) {
userScore++;
printf("User won this one!");
break;
} else {
cpuScore++;
printf("CPU won this one!");
break;
}
case 'S':
if(player1 == 'S' && player2 == 3) {
printf("Draw!");
break;
} else if(player1 == 'S' && player2 == 1) {
userScore++;
break;
printf("User won this one!");
} else {
cpuScore++;
printf("CPU won this one!");
break;
}
default :
printf("\nInvalid Input");
break;
}
printf("\nUser Score: %d", userScore);
printf("\nCPU Score: %d", cpuScore);
count++;
}
if(userScore == cpuScore) {
printf("\nDraw game!");
} else if(userScore > cpuScore) {
printf("\nYou win!");
} else {
printf("\nCPU wins!");
}
return 0;
} ```
尝试一下：
#include <stdio.h>
#include <stdlib.h>
int main () {
char player1;
int player2;
int userScore = 0, cpuScore = 0;
srand ((int) time (NULL));
int count = 0;
while(count != 10) {
printf("Enter p for Paper, r for rock, or S for scissor:\n");
fgets(&player1, 80, stdin);
player2 = rand ( ) % 4;
if(player1 == 'P' && player2 == 1) {
printf("Draw!\n");
}if(player1 == 'P' && player2 == 2) {
userScore++;
printf("User won this one!\n");
}if(player1 == 'P' && player2 == 3){
cpuScore++;
printf("CPU won this one!\n");
}
if(player1 == 'R' && player2 == 2) {
printf("Draw!\n");
}if(player1 == 'R' && player2 == 3) {
userScore++;
printf("User won this one!\n");
}if(player1 == 'R' && player2 == 1){
cpuScore++;
printf("CPU won this one!\n");
}
if(player1 == 'S' && player2 == 3) {
printf("Draw!\n");
}if(player1 == 'S' && player2 == 1) {
userScore++;
printf("User won this one!\n");
}if(player1 == 'S' && player2 == 2){
cpuScore++;
printf("CPU won this one!\n");
}
if(player1!='S' || player1!='R' || player1!='P'){
printf("Invalid Input\n");
}
printf("User Score: %d\n", userScore);
printf("CPU Score: %d\n", cpuScore);
count++;
}
if(userScore == cpuScore) {
printf("Draw game!\n");
} else if(userScore > cpuScore) {
printf("You win!\n");
} else {
printf("CPU wins!\n");
}
return 0;
}
我还应该补充一点，该程序是敏感的。例如，输入“ r”将不起作用，但输入“ R”将起作用。您可以自行决定更改此设置。
我建议您修复它，以免使其复杂得多。剪刀石头布的获胜者可以通过算法确定。
比较起来比较简单，使用整数值可以使用更简单的算术解决方案。同样从算术上来说，使用0,1,2而不是1,2,3更简单。因此，首先将用户输入转换为0,1,2：
#define INVALID_SELECTION sizeof(rps)
static const char rps[] = {'r', 'p', 's'} ;
int human = INVALID_SELECTION ;
while( human == INVALID_SELECTION )
{
printf("\nEnter R for Rock, P for Paper, or S for Scissors: ");
char ch = 0 ;
scanf("%c", &ch ) ;
while( ch != '\n' && getchar() != '\n' ) ;
for( human = 0;
human < INVALID_SELECTION && tolower(ch) != rps[human] ;
human++ )
{
// do nothing
}
}
然后应确定计算机的播放方式：
srand( (int)time(NULL) ) ;
int computer = rand() % 3 ;
尽管请注意，您只需要调用一次srand()，所以如果将游戏置于循环中以重复播放，则srand()调用应出现在[[before重复循环中。
static const char* play_lookup[] = { "Rock", "Paper", "Scissors" } ;
printf( "Human played %s\n", play_lookup[human] ) ;
printf( "Computer played %s\n", play_lookup[computer] ) ;
然后human和computer在算术上是直接可比的，使得：
int battle = human - computer ; if( battle < 0 ) battle += 3 ; switch( battle ) { case 0 : printf( "Draw!\n" ) ; break ; case 1 : printf( "Human wins!\n" ) ; break ; case 2 : printf( "Computer wins!\n" ) ; break ; }
全部放在一起：
#include <stdio.h> #include <stdlib.h> #include <ctype.h> int main() { // Randomize srand( (int)time(NULL) ) ; // Repeat play indefinitely for(;;) { #define INVALID_SELECTION sizeof(rps) static const char rps[] = {'r', 'p', 's'} ; int human = INVALID_SELECTION ; // While human input is not one of R,P,S,r,p or s... while( human == INVALID_SELECTION ) { printf("\nEnter R for Rock, P for Paper, or S for Scissors: "); char ch = 0 ; scanf("%c", &ch ) ; while( ch != '\n' && getchar() != '\n' ) ; // Transform input to one of 0,1,2 (for R,P,S respectively) for( human = 0; human < INVALID_SELECTION && tolower(ch) != rps[human] ; human++ ) { // do nothing } } // Get computer's play int computer = rand() % 3 ; // Report human and computer plays in full text static const char* play_lookup[] = { "Rock", "Paper", "Scissors" } ; printf( "Human played %s\n", play_lookup[human] ) ; printf( "Computer played %s\n", play_lookup[computer] ) ; // Calculate and report result int battle = human - computer ; if( battle < 0 ) battle += 3 ; switch( battle ) { case 0 : printf( "Draw!\n" ) ; break ; case 1 : printf( "Human wins!\n" ) ; break ; case 2 : printf( "Computer wins!\n" ) ; break ; } } return 0; }
示例输出：
Enter R for Rock, P for Paper, or S for Scissors: r Human played Rock Computer played Rock Draw! Enter R for Rock, P for Paper, or S for Scissors: r Human played Rock Computer played Scissors Human wins! Enter R for Rock, P for Paper, or S for Scissors: r Human played Rock Computer played Rock Draw! Enter R for Rock, P for Paper, or S for Scissors: r Human played Rock Computer played Scissors Human wins! Enter R for Rock, P for Paper, or S for Scissors: r Human played Rock Computer played Paper Computer wins! Enter R for Rock, P for Paper, or S for Scissors: p Human played Paper Computer played Paper Draw! Enter R for Rock, P for Paper, or S for Scissors: p Human played Paper Computer played Scissors Computer wins! Enter R for Rock, P for Paper, or S for Scissors: p Human played Paper Computer played Rock Human wins! Enter R for Rock, P for Paper, or S for Scissors: s Human played Scissors Computer played Scissors Draw! Enter R for Rock, P for Paper, or S for Scissors: s Human played Scissors Computer played Paper Human wins! Enter R for Rock, P for Paper, or S for Scissors: s Human played Scissors Computer played Paper Human wins! Enter R for Rock, P for Paper, or S for Scissors: s Human played Scissors Computer played Scissors Draw! Enter R for Rock, P for Paper, or S for Scissors: s Human played Scissors Computer played Rock Computer wins! Enter R for Rock, P for Paper, or S for Scissors: R Human played Rock Computer played Scissors Human wins! Enter R for Rock, P for Paper, or S for Scissors: P Human played Paper Computer played Paper Draw! Enter R for Rock, P for Paper, or S for Scissors: S Human played Scissors Computer played Paper Human wins! Enter R for Rock, P for Paper, or S for Scissors: xx Enter R for Rock, P for Paper, or S for Scissors: yy Enter R for Rock, P for Paper, or S for Scissors: zz Enter R for Rock, P for Paper, or S for Scissors:
player2，而不更新它；它会一直不变。与其将其转换为toupper的中间值，不如将其直接转换为enum的典型情况。而不是将switch与if一起使用，这会将您的问题空间缩小到3个值，这很容易放在查找表中。]#include <stdlib.h>
#include <stdio.h> /* `printf` requires this. */
#include <time.h>
/* https://en.wikipedia.org/wiki/X_Macro just because I don't want to type. */
#define CHOICE(X) X(ROCK), X(PAPER), X(SCISSORS)
#define OUTCOME(X) X(LOSS), X(TIE), X(WIN)
#define NAME(A) A
#define STR(A) #A
enum Choice { CHOICE(NAME) };
static const char *const choice_names[] = { CHOICE(STR) };
enum Outcome { OUTCOME(NAME) };
static const char *const outcome_names[] = { OUTCOME(STR) };
static enum Outcome choice_outcomes[][3] = {
{ TIE, LOSS, WIN },
{ WIN, TIE, LOSS },
{ LOSS, WIN, TIE }
};
int main(void) { /* <- `void` should be used to prototype. */
char input;
enum Choice player1, player2;
int score[] = { 0, 0, 0 }; /* <- Replace `cpuScore` and `userScore`. */
int count = 0;
srand ((int) time (NULL)); /* <- `srand` should precede `rand`. */
while(count <= 10) {
printf("\nEnter p for Paper, r for rock, or S for scissor: ");
/* Ignores whitespace, (_viz_ enter); breaks on error, (_eg_ EOF.) */
if(scanf(" %c", &input) != 1) break;
/* Convert it to `player1` immediately. */
switch(input) {
case 'r': case 'R':
player1 = ROCK; break;
case 'p': case 'P':
player1 = PAPER; break;
case 's': case 'S':
player1 = SCISSORS; break;
default:
printf("Unexpected input, '%c'.\n", input); continue;
}
player2 = rand() % 3;
printf("User choses %s _vs_ Cpu choses %s: %s.\n",
choice_names[player1], choice_names[player2],
outcome_names[choice_outcomes[player1][player2]]);
score[choice_outcomes[player1][player2]]++;
printf("User Score: %d\n", score[WIN]);
printf("CPU Score: %d\n", score[LOSS]);
printf("Ties: %d\n", score[TIE]);
count++;
}
/* One of the places was the `scanf` break, so check, (unlikely.) */
if(ferror(stdin)) { perror("stdin"); return 1; }
/* Print the winner. */
if(score[WIN] == score[LOSS]) {
printf("Draw game!\n");
} else if(score[WIN] > score[LOSS]) {
printf("You win!\n");
} else {
printf("CPU wins!\n");
}
return 0;
}
我还将userScore和cpuScore放入由enum Outcome索引的数组中。