如何在Google App Engine上为postgresql设置flask-admin和flask-sqlalchemy?

问题描述 投票:0回答:1

我正在尝试在Google App Engine上使用flask-admin和flask-sqlalchemy,但出现以下错误:

pg8000.core.ProgrammingError:{'S':'ERROR','V':'ERROR','C':'42P18','M':'无法确定参数$ 1的数据类型','F ':'postgres.c','L':'1400','R':'exec_parse_message'}

sqlalchemy.exc.ProgrammingError:(pg8000.core.ProgrammingError){'S':'ERROR','V':'ERROR','C':'42P01','M':'关系“用户”不存在”,“ P”:“ 239”,“ F”:“ parse_relation.c”,“ L”:“ 1180”,“ R”:“ parserOpenTable”}

KeyError:('SELECT count(%s)AS count_1 \ nFROM属性',(((705,0,.text_out at 0x7f8a723b8c80>),))

我在访问某些flask-admin视图(CRUD视图)时收到这些错误。但是,当我在不使用flask-admin的情况下使用非Flask-admin表单和其他数据库操作时,我的应用程序可以在Google App Engine上正常运行。

我的设置在下面列出

from flask import Flask
from config import Config
from flask_sqlalchemy import SQLAlchemy
from flask_migrate import Migrate
from flask_login import LoginManager
from flask_bootstrap import Bootstrap
from flask_admin import Admin

# APP setup
app = Flask(__name__)
app.config.from_object(Config)

# Databaset setup
db = SQLAlchemy(app)
migrate = Migrate(app, db)

# Bootstrap setup
bootstrap = Bootstrap(app)

# Login setup
login = LoginManager(app)
login.login_view = 'login'

from app import models


# Start Application
@app.before_first_request
def setup():

    db.create_all()

    # Creating default users, group and role
    if not models.User.query.first():

        attributes = {...}

        for k, v in attributes.items():
            attr = models.Attribute(name=k, type=v)
            db.session.add(attr)

        role = models.Role(name='admin')

        group = models.Group(name='Administrator')
        group.roles.append(role)

        user = models.User(username='admin')
        user.set_password('admin')
        user.groups.append(group)

        db.session.add(user)
        db.session.commit()


from app.views import GeneralModelView, UserModelView, RoleModelView, GroupModelView, MyAdminIndexView

# Admin Setup
admin = Admin(app, name='Administration', index_view=MyAdminIndexView())
admin.add_view(RoleModelView(models.Role, db.session))
admin.add_view(GroupModelView(models.Group, db.session))
admin.add_view(UserModelView(models.User, db.session))
admin.add_view(GeneralModelView(models.Model, db.session))
admin.add_view(GeneralModelView(models.ModelVersion, db.session))
admin.add_view(GeneralModelView(models.Attribute, db.session))


# Start Application
from app import routes

我的配置定义如下。

import os

basedir = os.path.abspath(os.path.dirname(__file__))


class Config(object):

    SECRET_KEY = os.environ.get('SECRET_KEY') or 'my-super-key-is-here'

    SQLALCHEMY_TRACK_MODIFICATIONS = False

    SQLALCHEMY_DATABASE_URI = os.environ.get('DATABASE_URI') or \
        'sqlite:///' + os.path.join(basedir, 'app.db')

我的app.yaml定义如下:

runtime: python
env: flex
entrypoint: gunicorn -b :$PORT hub:app

runtime_config:
  python_version: 3

beta_settings:
  cloud_sql_instances: <instance>

env_variables:
  DATABASE_URI: 'postgres+pg8000://<user>:<password>?unix_sock=/cloudsql/<instance>/.s.PGSQL.5432'


manual_scaling:
  instances: 1
resources:
  cpu: 1
  memory_gb: 0.5
  disk_size_gb: 10

请,我该如何解决这个问题?我的所有应用程序都可以正常工作,但flask-admin视图除外。我的表和数据保存在安装在Google Cloud SQL(PostgreSQL 11)上的数据库中。

python postgresql google-app-engine flask-sqlalchemy flask-admin
1个回答
2
投票

我解决了将驱动程序从pg8000更改为psycopg2的问题。在我的代码中,我只是从[]更新DATABASE_URI

postgres+pg8000://<user>:<password>@?unix_sock=/cloudsql/<instance>/.s.PGSQL.5432

postgres+psycopg2://<user>:<password>@/<database>?host=/cloudsql/<instance>

[psycopg2使用host参数接收unix套接字,并且只需要目录路径,而不需要文件1作为pg8000

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