当我使用
QTreeWidget
以编程方式在 item_selected('Item2')
中选择一个选项时,该选项将按预期传递到处理程序。我还希望该项目有一个选择突出显示,但我似乎无法弄清楚。有什么想法吗?
from PyQt5.Qt import Qt
from PyQt5.QtWidgets import QApplication, QTreeWidget, QTreeWidgetItem
import sys
def item_selected(selection):
try:
print(selection.text(0))
except AttributeError:
print(selection)
app = QApplication(sys.argv)
TreeList = ({
'Header1': (('Item1', 'Item2', )),
'Header2': (('Item11', 'Item21', )),
})
tree = QTreeWidget()
for key, value in TreeList.items():
parent = QTreeWidgetItem(tree, [key])
for val in value:
child = QTreeWidgetItem([val])
child.setFlags(child.flags() | Qt.ItemIsUserCheckable)
child.setCheckState(0, Qt.Unchecked)
parent.addChild(child)
tree.itemClicked.connect(item_selected)
tree.show()
# SELECT AND HIGHLIGHT THIS ONE
item_selected('Item2')
sys.exit(app.exec_())
如果上面的代码有点混乱,抱歉。
您不能使用相同的插槽,它接收一个项目,并且仅打印它,在您的情况下,您必须搜索该项目的文本并选择它:
def item_selected(selection):
print(selection.text(0))
app = QApplication(sys.argv)
TreeList = ({
'Header1': (('Item1', 'Item2', )),
'Header2': (('Item11', 'Item21', )),
})
tree = QTreeWidget()
for key, value in TreeList.items():
parent = QTreeWidgetItem(tree, [key])
for val in value:
child = QTreeWidgetItem([val])
child.setFlags(child.flags() | Qt.ItemIsUserCheckable)
child.setCheckState(0, Qt.Unchecked)
parent.addChild(child)
tree.itemClicked.connect(item_selected)
items = tree.findItems("Item2", Qt.MatchFixedString| Qt.MatchRecursive)
[it.setSelected(True) for it in items]
tree.expandAll()
tree.show()
sys.exit(app.exec_())