如何解决“无法准备上下文：找不到路径“Dockerfile.xxx””错误

Question

我正在做一个运行 TCP 聊天室的项目，该项目应该使用 docker-compose 进行容器化和构建。一切都很好，直到尝试构建：

$docker build Dockerfile.server
[+] Building 0.0s (0/0)                                                          docker:default                                                                                                            ERROR: unable to prepare context: path "Dockerfile.server" not found

我的文件结构

.
└── projee docker-chatroom
    └── docker-compose.yml
    └── Dockerfile.server
    └── Dockerfile.client
    └── serveryt.py
    └── clientyt.py
    └── logs
        └── ...

---

serveryt.py：

import threading
import socket
import logging

# Logging ayarları
logging.basicConfig(filename='logs/server.log', level=logging.INFO,
                    format='%(asctime)s - %(name)s - %(levelname)s - %(message)s')

host = '127.0.0.1'  # Tüm IP adreslerinden bağlantı kabul edilecek
port = 33333

sv = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
sv.bind((host, port))
sv.listen()

cl = []
name = []


def broadcast(message):
    for client in cl:
        client.send(message)


def handle(cl):
    while True:
        try:
            message = cl.recv(1024)
            broadcast(message)

        except:
            index = cl.index(cl)
            cl.remove(cl)
            cl.close()
            nickname = name[index]
            broadcast(f'{nickname} left the chat.'.encode('ascii'))
            name.remove(nickname)
            logging.info(f'{nickname} left the chat.')
            break


def receive():
    while True:
        client, adrs = sv.accept()
        logging.info(f'Connected with {str(adrs)}')

        client.send('Name:'.encode('ascii'))
        nickname = client.recv(1024).decode('ascii')
        name.append(nickname)
        cl.append(client)

        logging.info(f"Name of the client is {nickname}.")
        broadcast(f"{nickname} connected to the chat.".encode('ascii'))
        client.send('Connected to the chat.'.encode('ascii'))

        thread = threading.Thread(target=handle, args=(client,))
        thread.start()


logging.info("Server is listening...")
receive()

---

clientyt.py

import socket
import threading
import os
import time

name = os.getenv("USERNAME")
if not name:
    raise ValueError("USERNAME environment variable not set")

cl = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

while True:
    try:
        cl.connect(('server', 33333))  # '127.0.0.1' yerine 'server' kullanıyoruz
        break
    except ConnectionRefusedError:
        print("Server henüz başlatılmadı, 5 saniye sonra tekrar denenecek...")
        time.sleep(5)

def recieve():
    while True:
        try:
            message = cl.recv(1024).decode('ascii')
            if message == 'Name:':
                cl.send(name.encode('ascii'))
            else:
                print(message)
        except:
            print("An error occurred")
            cl.close()
            break

def write():
    while True:
        message = f'{name}: {input("")}'
        cl.send(message.encode('ascii'))

rc_th = threading.Thread(target=recieve)
rc_th.start()

wr_th = threading.Thread(target=write)
wr_th.start()

---

Dockerfile.server：

# Dockerfile.serveryt
FROM python:3.9-slim

WORKDIR /app

COPY serveryt.py .

RUN pip install scikit-learn

CMD ["python", "serveryt.py"]

---

Dockerfile.client：

# Dockerfile.clientyt
FROM python:3.9-slim

WORKDIR /app

COPY clientyt.py .

CMD ["python", "clientyt.py"]

docker-compose.yml

version: '3.8'

services:
  server:
    build:
      context: .
      dockerfile: Dockerfile.serveryt
    ports:
      - "33333:33333"
    volumes:
      - ./logs:/app/logs
    logging:
      driver: "json-file"
      options:
        max-size: "10m"
        max-file: "3"
    container_name: chatroom_server

  client:
    build:
      context: .
      dockerfile: Dockerfile.clientyt
    depends_on:
      - server
    environment:
      - USERNAME=YourName  # Enter nickname
    container_name: chatroom_client

问题是什么？我还是没明白。我认为这可能是权限问题，但 docker 具有 root 访问权限。

我尝试了旧的堆栈溢出帖子解决方案，但没有成功

Answer 1

正如 docker 构建文档所述：如果 Dockerfile 名称不是

Dockerfile

，则需要使用

-f

选项。

所以你应该使用这个命令来构建：

docker build -f Dockerfile.server .

docker build -f Dockerfile.client .

您的

docker-compose.yml

文件中的 dockerfile 名称也不正确。

您还可以使用

docker compose up

命令来构建、创建和启动容器。